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astraxan [27]
3 years ago
9

Solve this problem show work.-5/6 + 1/3​

Mathematics
1 answer:
kati45 [8]3 years ago
4 0

Answer:

-1/2

Step-by-step explanation:

steps are in picture.

If you are having confusion just ask .I'll give you answer.

You might be interested in
6. If rls and mZ1 = 35º, what is mZ2?<br> 2<br> 1<br> S<br> please help!!
disa [49]

Answer:

55

Step-by-step explanation:

along line s, r intersects it, and you can see a right angle

90+35+angle 2 =180

you end up with 55, which is the measure

4 0
3 years ago
Read 2 more answers
Amy raised £n for charity. Chris raised £18 more than Amy.
malfutka [58]
Amy=n
Chris=n+18

Mean:
45= \frac{(n)+(n+18)}{2}
So, 45=n+9
Therefore, n=36

Amy=n=36pounds
Chris=n+18=54pounds

Hope I helped :)

(Sorry I was late for you other question)
7 0
4 years ago
Bobby has $27 to spend on ice cream for the month. The ice cream he likes is $2 each. How many ice creams can he buy this month?
LuckyWell [14K]

Answer:

13

Step-by-step explanation:

Divide:

27 ÷ 2 = 13 r1

So, he can buy 13 but has a dollar left.

Hope this helps you out! : )

8 0
3 years ago
Please help with these partial fractions!!!
VARVARA [1.3K]

a. Factorize the denominator:

\dfrac{x+14}{x^2-2x-8}=\dfrac{x+14}{(x-4)(x+2)}

Then we're looking for a,b such that

\dfrac{x+14}{x^2-2x-8}=\dfrac a{x-4}+\dfrac b{x+2}

\implies x+14=a(x+2)+b(x-4)

If x=4, then 18=6a\implies a=3; if x=-2, then 12=-6b\implies b=-2. So we have

\dfrac{x+14}{x^2-2x-8}=\dfrac3{x-4}-\dfrac2{x+2}

as required.

b. Same setup as in (a):

\dfrac{-3x^2+5x+6}{x^3+x^2}=\dfrac{-3x^2+5x+6}{x^2(x+1)}

We want to find a,b,c such that

\dfrac{-3x^2+5x+6}{x^2(x+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac c{x+1}

Quick aside: for the second term, since the denominator has degree 2, we should be looking for another constant b' such that the numerator of the second term is b'x+b. We always want the polynomial in the numerator to have degree 1 less than the degree of the denominator. But we would end up determining b'=0 anyway.

\implies-3x^2+5x+6=ax(x+1)+b(x+1)+cx^2

If x=0, then b=6; if x=-1, then c=-2. Expanding everything on the right then gives

-3x^2+5x+6=ax^2+ax+bx+b+cx^2=(a-2)x^2+(a+6)x+6

which tells us a-2=-3 and a+6=5; in both cases, we get a=-1. Then

\dfrac{-3x^2+5x+6}{x^2(x+1)}=-\dfrac1x+\dfrac6{x^2}-\dfrac2{x+1}

as required.

5 0
4 years ago
Compare adding unlike fractions and adding like fractions
muminat

Answer:

We just add numerators and rewrite denominator.

Adding unlike dominators:

We need to find the same denominators. You need to find the least common multiple (LCM) of the two denominators.

Step-by-step explanation:

You mean unlike denominators and like denominators.

Adding like dominators: We just add numerators and rewrite denominator :

Example : \frac{1}{4} +\frac{2}{4}=\frac{1+2}{4}  =\frac{3}{4}

Adding unlike dominators:

We need to find the same denominators. You need to find the least common multiple (LCM) of the two denominators.

For example :

\frac{1}{5}+\frac{3}{4}

LCM for 5 and 4 is 20 : Now, divide by 5 and multiply by 1 for first fraction. 20 divide by 4 and multiply by 3 :

\frac{1*4}{20} +\frac{3*5}{20}=\frac{4}{20} +\frac{15}{20}=\frac{19}{20}

4 0
3 years ago
Read 2 more answers
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