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2 years ago

The sum of 4 consecutive integers is 406. find the integers

Mathematics

2 answers:

BabaBlast [244]2 years ago

8 0

Answer and Step-by-step explanation:

When trying to figure this out, we know that the numbers have to be one after the other, like 1, 2, 3, 4, or 55. 56, 57, 58. The last digit in the numbers also have to add to 6.

The answer is:

100 + 101 + 102 + 103

It adds up to 406, and the integers are consecutive.

#teamtrees #PAW (Plant And Water)

I hope this helps!

gulaghasi [49]2 years ago

8 0

Answer:

Step-by-step explanation:

let the numbers be n,n+1,n+2,n+3

n+n+1+n+2+n+3=406

4n+6=406

4n=406-6=400

n=400/4=100

then the numbers are

100,100+1,100+2,100+3

100,101,102,103

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2 years ago

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2 years ago

Circles M and K are congruent, QR is congrent to LN. Find the length of QR

Novosadov [1.4K]

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So, QR = LN

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4x + 2 = x + 7

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So, $x=\frac{5}{3}$

Next step is to plug in $x=\frac{5}{3}$ in QR = 4x+2 to get length of QR.

So, $QR = 4(\frac{5}{3})+2$

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2 years ago

The sum of the first 150 negative integers is represented using the expression What is the sum of the first 150 negative integer

Kamila [148]

Answer:

C. -11,325

Step-by-step explanation:

To know the answer, is convenient to replace some values of "n" in the sum $\sum_{(n=1)}^{150}[-1-(n-1)]$ .

The result would appear after adding up every value of the expression $\sum_{(n=1)}^{150}[-1-(n-1)]$ when n=1,2,3.....,150.
When n=1, the expression takes the value of (-1): $[-1-(1-1)]= (-1)-0=-1$ .
When n=2, the expression takes the value of (-2): $[-1-(2-1)]=-1-1=-2$ .
Following this way, for every n, we will obtain -n, then, the sum will be: $-1-2-3-4-5-6-...-150$ . This sum can actually be expressed as $\sum_{n=1}^{150}(-n)$ , which is the result of solving the initial expression of the sum $-1-(n-1)=-1-n+1=-n$ .
Finally, the sum of n=-1 to n=-150 equals -11,325.

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3 years ago

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