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2 years ago

The sum of 4 consecutive integers is 406. find the integers

Mathematics

2 answers:

BabaBlast [244]2 years ago

8 0

Answer and Step-by-step explanation:

When trying to figure this out, we know that the numbers have to be one after the other, like 1, 2, 3, 4, or 55. 56, 57, 58. The last digit in the numbers also have to add to 6.

The answer is:

100 + 101 + 102 + 103

It adds up to 406, and the integers are consecutive.

#teamtrees #PAW (Plant And Water)

I hope this helps!

gulaghasi [49]2 years ago

8 0

Answer:

Step-by-step explanation:

let the numbers be n,n+1,n+2,n+3

n+n+1+n+2+n+3=406

4n+6=406

4n=406-6=400

n=400/4=100

then the numbers are

100,100+1,100+2,100+3

100,101,102,103

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AB = [ 4 ]. Find A if B=(22]

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A = 2/11

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2 years ago

Three times as many children as adults attended a concert on Saturday. An adult ticket cost $7 and a child’s ticket cost $3. The

Ierofanga [76]

For this case we propose a system of equations:

x: Let the variable representing the number of children in the concert

y: Let the variable representing the number of adults at the concert

According to the assistance we have:

$x = 3y$

According to the cost we have:

$3x + 7y = 6000$

Substituting the first in the second equation we have:

$3 (3y) + 7y = 6000\\9y + 7y = 6000\\16y = 6000\\y = \frac {6000} {16}\\y = 375$

Thus, the concert was 375 adults.

On the other hand we have:

$x = 3 (375) = 1125$

Thus, the concert was 1125 children.

In total they were:

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2 years ago

In the adjoining figure , APB and AQC are equilateral triangles. Prove that PC = BQ. ( Hint : <img src="https://tex.z-dn.net/?f=

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Answer:

See Below.

Step-by-step explanation:

Statements: Reasons:

$\displaystyle 1)\text{ } \Delta APB \text{ and } \Delta AQC \text{ are equilateral triangles}$ Given

$\displaystyle 2) \text{ } m \angle PAB = 60$ Definition of equilateral.

$3)\text{ } m \angle QAC = 60$ Definition of equilateral.

$4)\text{ } m\angle PAB = m\angle QAC$ Substitution

$5)\text{ } m\angle PAC=m\angle PAB+m\angle BAC$ Angle Addition

$\displaystyle 6)\text{ } m\angle QAB=m\angle QAC+m\angle BAC$ Angle Addition

$7)\text{ } m\angle QAB=m\angle PAB+m\angle BAC$ Substitution

$\displaystyle 8)\text{ } m\angle PAC=m\angle QAB$ Substitution

$9)\text{ } PA=BA$ Definition of equilateral

$10)\text{ } AC=AQ$ Definition of equilateral

$\displaystyle 11)\text{ } \Delta PAC \cong \Delta BAQ$ Side-Angle-Side Congruence*

$\displaystyle 12)\text{ } PC=BQ$ CPCTC

* SAS Congruence:

PA = BA

∠PAC = ∠QAB

AC = AQ

6 0

2 years ago

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