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MAXImum [283]
3 years ago
6

It is possible to create a semi regular tessellation using only squares and regular hexagons?

Mathematics
1 answer:
pogonyaev3 years ago
7 0

Answer:

Yes

Step-by-step explanation:

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Express the decimal 0.43 as a fraction in its simplest form.
maks197457 [2]

Answer:

Step-by-step explanation:

43/100 or  43%

3 0
3 years ago
Lucy fills a bathroom sink with water. Is the amount of water more than one liter, about one liter, or less than one liter . Exp
seropon [69]
More than one liter because it only depends how bog your sink is...I believe it is more than one liter
6 0
4 years ago
An item is regularly priced at $85 . it is on sale for 60% off the regular price. how much (in dollars) is discounted from the r
Alex_Xolod [135]
100% - 60% = 40%
 40% = 85 
 1% = 85 / 40 
100% = 85/ 40 × 100
 100% = $ 212.5.
6 0
3 years ago
Marcel bought a new pair of inline skates. Each
g100num [7]

Answer:

1288.05

Explanation:

41mm=r

2(pi)r=257.61

257.61x5=1288.05

4 0
3 years ago
Please please help me out
Dafna1 [17]

Answer:

The slant height of the pyramid is 3√2 ft, or to the nearest tenth ft,

4.2 ft

Step-by-step explanation:

The equation for the volume of a pyramid of base area B and height h is

V = (1/3)·B·h.  Here, V = 432 ft³, B = (12 ft)² and h (height of the pyramid) is unknown.  First we find the height of this pyramid, and then the slant height.

V = 432 ft³ = (144 ft²)·h, so h = (432 ft³) / (144 ft²) = 3 ft.

Now to find the slant height of this pyramid:  That height is the length of the hypotenuse of a right triangle whose base length is half of 12 ft, that is, the base length is 6 ft, and the height is 3 ft (as found above).

Then hyp² = (3 ft)(6 ft) = 18 ft², and the hyp (which is also the desired slant height) is hyp = √18, or √9√2, or 3√2 ft.

The slant height of the pyramid is 3√2 ft, or to the nearest tenth ft,

4.2 ft

5 0
3 years ago
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