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2 years ago

What is the distance between (-6,8) and (-3,9)?

Mathematics

2 answers:

zvonat [6]2 years ago

5 0

Answer:

3.162278

Step-by-step explanation:

d = √ (−3 − ( −6 ) )^2 + ( 9 − 8 )^2

d = √(3)^2+(1)^2

d = √9+1

d = √10

d = 3.162278

yKpoI14uk [10]2 years ago

3 0

The midpoint is: (-4.5,8.5)

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Oil spill spreads 25 m² every 1/6 hour how much area does the oil spill cover after two hours

Delvig [45]

1/6 of an hour is 10 minutes because there are 60 minutes in an hour so 60/6=10
so it's 25m^2/10minutes
now just multiply 25 by 12 ( 12 lots of 10 minutes in 2 hours)
25*12=300
answer is 300m^2

hope this helped

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2 years ago

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Question 3 (1 point)

solong [7]

Answer:

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4 * 8 - 4 *7 =?

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2 years ago

What is the do.ain and range of (1,9), (2,7), (5,4), (7,12) (3,9)

inysia [295]

Domain: {1,2,3,5,7}
Range: {4,9,7,12}

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2 years ago

Answer these questions about the powers of 3. What is the pattern as the exponents decrease? What is the value of each variable?

avanturin [10]

Answer:

divide by 3

a=1, b=1/3, c=1/27

Step-by-step explanation:

plz thank if correct

4 0

3 years ago

Read 2 more answers

Need help please!! Will give points

Nataly [62]

Answer:

1. $\bar X=5.10$

2. $\sigma=0.47$

3. $\sigma^2=0.22$

Step-by-step explanation:

QUESTION 1

The given data set for the expenditure is

$4.85,5.10,5.50,4.75,4.50,5.00,6.00$

The formula for calculating the mean is given by,

$\bar X=\frac{\sum x}{n}$

We need to add all the expenditure and divide by the total number of days.

$\bar X=\frac{4.85+5.10+5.50+4.75+4.50+5.00+6.00}{7}$

This gives us,

$\bar X=\frac{35.7}{7}$

$\Rightarrow \bar X=5.10$ to the nearest hundredth.

QUESTION 2

The standard deviation of the data set is given by the formula;

$\sigma =\sqrt{\frac{\sum(x-\bar X)^2}{n} }$

This implies that,

$\sigma =\sqrt{\frac{(4.85-5.10)^2+(5.10-5.10)^2+(5.50-5.10)^2+(4.75-5.10)^2+(4.50-5.10)^2+(5.00-5.10)^2+(6.00-5.10)^2}{7} }$

This will give us,

$\sigma =\sqrt{\frac{(-0.25)^2+(0.00)^2+(0.40)^2+(-0.35)^2+(-0.60)^2+(-0.10)^2+(0.90)^2}{7} }$

$\sigma =\sqrt{\frac{0.0625+0+0.16+0.1225+0.36+0.01+0.81}{7} }$

$\sigma =\sqrt{\frac{61}{280} }$

$\sigma =0.466775$

to the nearest hundredth,

$\sigma =0.47$ .

QUESTION 3

The variance is the square of the standard deviation.

$\sigma^2 =(0.46675)^2$

$\sigma^2 =0.217857$

To the nearest hundred gives,

$\sigma^2 =0.22$

3 0

3 years ago