Answer: lol i may be wrong but...
Step-by-step explanation: im
pretty sure the equation would 5(x+4)=_
and the amount of money his parent put in was also $4 evreyday for 5 days.
Answer:
Yes
With an extra 3000CHF
Step-by-step explanation:
In year 2005, the exchange rate was 1$ = 1.15CHF
The student came in with $20,000.
The amount he had in CHF(swiss franc) = ?
$1 = 1.15C
$20,000 = x CHF
X = (20000 × 1.15) / 1
X = 23,000CHF
When he came to Zürich in 2005, he has 23,000 swiss franc.
But the exchange rates changed in 2006 to C1.30 against the dollar.
$1 = 1.30CHF
$20,000 = xCHF
X = 26,000CHF
In 2006, he would've had 26,000CHF.
The difference between what he would've had in 2006 against 2005 is
26,000CHF - 23,000CHF = 3000CHF
He would've had an extra 3000CHF if he came in the year 2006.
Answer:
Option B is the correct answer
Step-by-step explanation:
Answer:
15% is reduced
Step-by-step explanation:
I always start by finding what 10% and 5% is, after that, I try to see how I can make that into the number subtracted and for this it happened to be 15% I found that 10% was 14,400 and 5% was 7,200 and I found the total amount reduced was 21,600 which is 14,400+7,200 or 10%+5%