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2 years ago

Hcf of x^2 + 2x - y^2 + 2y

Mathematics

2 answers:

11111nata11111 [884]2 years ago

8 0

Answer:

$(x + y) \times (x - y + 2)$

Step-by-step explanation:

$x^{2} + 2x - {y}^{2} + 2y$

➡️ $(x - y) \times (x + y) + 2(x + y)$

➡️ $(x + y) \times (x - y + 2)$

borishaifa [10]2 years ago

3 0

(x^2-y^2)+(2x+2y)= (x+y).(x-y) +2.(x+y) = (x+y).(x-y+2)

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$\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
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\end{array}\\ \quad \\
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and also

$\bf \begin{array}{llllll}
\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\
\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\
y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}
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\end{array}
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now, we know that V varies directly to T and inversely to P simultaneously
thus $\bf V=T\cdot \cfrac{k}{P}$

so $\bf V=T\cdot \cfrac{k}{P}\qquad 
\begin{cases}
V=42\\
T=84\\
P=8
\end{cases}\implies 42=\cfrac{84k}{8}\implies 4=k
\\\\\\
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\begin{cases}
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3 years ago

Hcf of x^2 + 2x - y^2 + 2y​

Hcf of x^2 + 2x - y^2 + 2y