Answer:
8.90 seconds
Step-by-step explanation:
When the rocket hits the ground, its height ( <em>y</em> ) will be zero. This means we can write the equation as:
So we need to <u>solve that equation</u>:
x₁ = -0.84
x₂ = 8.90
We discard x₁, as it is negative.
So the answer is x₂, 8.90 seconds.
1) If a die is rolled once, determine the probability of rolling a 4: Rolling a 4 is an event with 1 favorable outcome (a roll of 4) and the total number of possible outcomes is 6 (a roll of 1, 2, 3, 4, 5, or 6). Thus, the probability of rolling a 4 is .
If a die is rolled once, determine the probability of rolling at least a 4: Rolling at least 4 is an event with 3 favorable outcomes (a roll of 4, 5, or 6) and the total number of possible outcomes is again 6. Thus, the probability of rolling at least a 4 is =
.
If a coin is flipped twice, determine the probability that it will land heads both times:
Favorable outcomes: 1 -- HH
Possible outcomes: 4 -- HH, HT, TH, TT
Thus, the probability that the coin will land heads both times is .
If Dan grabs one sock from a drawer containing 3 white socks, 4 blue socks, and 5 yellow socks, what is the probability that he will grab a white sock?
Favorable outcomes: 3 (3 white socks)
Possible outcomes: 12 (3 white socks + 4 blue socks + 5 yellow socks)
Thus, the probability that Dan will grab a white sock is =
.
Step-by-step explanation:
ED is greater than BC
the line from B to ED ^ (which i drew ) the point it touches ED name it X. so EX will be 2 ( ED-BC)(6-4).
then u have a triangle. EX, XB and EB.
you have length of EX(2) and u have hypotenuse. so u can calculate XB using Pythagoras theorem.
15.1²=2²+XB²
15.1²-2²=XB²
224.01=XB²
XB=14.97
since XB and DC are parallel ( a rectangle is forming XBCD) so DC is also 14.97
