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3 years ago

8

Solve with steps: 2 cos(x) = square root 3 = 0 0

1 answer:

Damm [24]3 years ago

6 0

I am not pretty sure if this is the correct but try

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If i roll 2 dice what is the probability that neither of them are prime nor even?

Eduardwww [97]

Answer:

There are 3 prime numbers shown on the die: 2, 3 and 5. The probability of showing a prime number on a single die is 1/2, hence the probability of not showing a prime number is also 1/2. Total possible outcomes when two dice are rolled = 6*6 = 36. Total possible outcomes when two dice are rolled = 6*6 = 36.

4 0

3 years ago

50 points + brainliest

erica [24]

Answer:

8. B.

9. B.

10. B.

11. No answer choices.

Step-by-step explanation:

Yes, they are all actually B. Hope this helps!

7 0

3 years ago

Read 2 more answers

(x+2)^2+(x-3)^2-2x^2)

garri49 [273]

Answer:

<u>13 - 2x </u>

Step-by-step explanation:

(x +2)² + (x - 3)² - 2x²

<em>Expand.</em>

(x + 2)(x + 2) + (x - 3)(x - 3) - 2x²

x² + 2x + 2x + 4 + x² - 3x - 3x + 9 - 2x²

<em>Bring all the like terms together then simply.</em>

x² + x² - 2x² + 2x + 2x - 3x - 3x + 4 + 9

2x² - 2x² + 4x - 6x + 13

= <u>13 - 2x</u> (or <u>-2x + 13</u> )

4 0

3 years ago

Suppose that y varies inversely with x. Use the information to find k, and then choose the equation of variation. X=2 when y=2

Vlad1618 [11]

Answer:

see explanation

Step-by-step explanation:

Given that y varies inversely as x then the equation relating them is

y = $\frac{k}{x}$ ← k is the constant of variation

To find k use the condition

x = 2 when y = 2

k = yx = 2 × 2 = 4, hence

y = $\frac{4}{x}$ ← equation of variation

7 0

3 years ago

Consider the following hypothesis test. : : The following results are for two independent samples taken from two populations. Ex

I am Lyosha [343]

Answer:

$z = -1.53$ --- test statistic

$p = 0.1260$ --- p value

Conclusion: Fail to reject the null hypothesis.

Step-by-step explanation:

Given

$n_1 = 80$ $\bar x_1= 104$ $\sigma_1 = 8.4$

$n_2 = 70$ $\bar x_2 = 106$ $\sigma_2 = 7.6$

$H_o: \mu_1 - \mu_2 = 0$ --- Null hypothesis

$H_a: \mu_1 - \mu_2 \ne 0$ ---- Alternate hypothesis

$\alpha = 0.05$

Solving (a): The test statistic

This is calculated as:

$z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2} }}$

So, we have:

$z = \frac{104 - 106}{\sqrt{\frac{8.4^2}{80} + \frac{7.6^2}{70} }}$

$z = \frac{104 - 106}{\sqrt{\frac{70.56}{80} + \frac{57.76}{70}}}$

$z = \frac{-2}{\sqrt{0.8820 + 0.8251}}$

$z = \frac{-2}{\sqrt{1.7071}}$

$z = \frac{-2}{1.3066}$

$z = -1.53$

Solving (b): The p value

This is calculated as:

$p = 2 * P(Z < z)$

So, we have:

$p = 2 * P(Z < -1.53)$

Look up the z probability in the z score table. So, the expression becomes

$p = 2 * 0.0630$

$p = 0.1260$

Solving (c): With $\alpha = 0.05$ , what is the conclusion based on the p value

We have:

$\alpha = 0.05$

In (b), we have:

$p = 0.1260$

By comparison:

$p > \alpha$

i.e.

$0.1260 > 0.05$

So, we fail to reject the null hypothesis.

4 0

3 years ago