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3 years ago

Kathy runs a 26.2- mile marathon at an average pace of 6.2 minutes per mile how long will it take her to finish

2 answers:

7 0

$\bf \begin{array}{ccll}
minutes&miles\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
6.2&1\\
x&26.2
\end{array}\implies \cfrac{6.2}{x}=\cfrac{1}{26.2}\implies \cfrac{6.2\cdot 26.2}{1}=x$

that many minutes, which boils down to about 2hrs and 42 minutes and 26 seconds.

drek231 [11]3 years ago

6 0

Around 2:45:34
hope this helps

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3/6 and 1/2

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If you divide each side of the fraction by 2 it will give you 1/2.

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Trey and Brandon each bought a new hockey stick for $80.

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2 years ago

Please solve 5q+6=2q-2+q.

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Answer:

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Step-by-step explanation:

$5q + 6 = 2 q- 2 + q$

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2 years ago

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HELP PLEASE The 20% tip on a $8 sandwich

Bess [88]

Answer:

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Step-by-step explanation:

So, to find the persent of a number, we need to make the percent a decimal.

So, 20% is equal to 0.2

Then, we need to multiply 0.2*8

8.0

* 0.2

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1.6

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2 years ago

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Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees a

Ivenika [448]

Answer:

<h2>70 possible groups</h2>

Step-by-step explanation:

Given the total number of employee to be equal to 12 temporary employee.

Number of women employee = 5 women

Number of men employee = 12 - 5 = 7 men

If 4 will be hired as permanent employees, the possible ways they can be grouped so that the 4 temporary employees consists of 3 women and 1 man can be done by applying the combination formula.

Combination has to do with selection. For example, if r objects are to be selected from n pool of similar objects, this can be done in <em>nCr </em>different ways.

$nCr = \frac{n!}{(n-r)!r!}$

According to question, we are to select 3 women from 5 women and 1 man from 7 men. Based on similarity in sex, this can be done in (5C3* 7C1) different ways .

$5C3 * 7C1\\= \frac{5!}{(5-3)!3!} * \frac{7!}{(7-1)!1!}\\\\= \frac{5!}{2!3!} * \frac{7!}{6!1!}\\\\= \frac{5*4*3!}{3!*2} * \frac{7*6!}{6!*1}\\\\= \frac{20}{2} * \frac{7}{1}\\ \\= 10*7\\\\= 70\ possible\ groups$

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3 years ago