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Nady [450]
2 years ago
5

Divide $2604 into a ratio of 2:1.

Mathematics
1 answer:
yaroslaw [1]2 years ago
5 0

Answer : 2604 can be divided into 1736 and 868 in the ratio of 2:1.

Step-by-step explanation:

2x + x = 2604

or, 3x = 2604

or, x = 2604/3 = 868

so

2x = 2*868 = 1736

now

x = 868

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Write an equation that passes through the points (4,-1) and (2,- 2).
jenyasd209 [6]
y=  1/2(x)-3
6 0
3 years ago
A sample of blood pressure measurements is taken for a group of​ adults, and those values​ (mm Hg) are listed below. The values
nika2105 [10]

Answer:

For systolic pressure data:

\bar X =127.2\\\\S=17.91668\\\\CV=\frac{17.91668}{127.2}=0.14085

For diastolic pressure data:

\bar X =73.5\\\\S=12.54\\\\CV=\frac{73.5}{12.54}=0.17061

Systolic pressure is slightly less variable, among individuals in the sample, than diastolic pressure.

Step-by-step explanation:

The coefficient of variation is defined as the percentage relative variation of a set of data with respect to its average. And it is calculated like this:

CV=\frac{\bar X}{S}

S =\sqrt{\frac{1}{n-1} \sum_{i=1}^n (x_i-\bar{x})^2

\bar X={\frac{1}{n} \sum_{i=1}^n x_i

For systolic pressure data:

\bar X =127.2\\\\S=17.91668\\\\CV=\frac{17.91668}{127.2}=0.14085

For diastolic pressure data:

\bar X =73.5\\\\S=12.54\\\\CV=\frac{12.54}{73.5}=0.17061

It is observed that the systolic pressure shows greater standard deviation but less coefficient of variation. This is due to the greater magnitude of its measurement scale.

Systolic pressure is slightly less variable, among individuals in the sample, than diastolic pressure.

7 0
3 years ago
Question:
prohojiy [21]
Let f(x) = p(x)/q(x), where p and q are polynomials and reduced to lowest terms. (If p and q have a common factor, then they contribute removable discontinuities ('holes').) 
Write this in cases: 
(i) If deg p(x) ≤ deg q(x), then f(x) is a proper rational function, and lim(x→ ±∞) f(x) = constant. 
If deg p(x) < deg q(x), then these limits equal 0, thus yielding the horizontal asymptote y = 0. 
If deg p(x) = deg q(x), then these limits equal a/b, where a and b are the leading coefficients of p(x) and q(x), respectively. Hence, we have the horizontal asymptote y = a/b. 
Note that there are no obliques asymptotes in this case. ------------- (ii) If deg p(x) > deg q(x), then f(x) is an improper rational function. 
By long division, we can write f(x) = g(x) + r(x)/q(x), where g(x) and r(x) are polynomials and deg r(x) < deg q(x). 
As in (i), note that lim(x→ ±∞) [f(x) - g(x)] = lim(x→ ±∞) r(x)/q(x) = 0. Hence, y = g(x) is an asymptote. (In particular, if deg g(x) = 1, then this is an oblique asymptote.) 
This time, note that there are no horizontal asymptotes. ------------------ In summary, the degrees of p(x) and q(x) control which kind of asymptote we have. 
I hope this helps!
4 0
3 years ago
Need help on this question writing linear equations
Mrrafil [7]

if you look at delta y over x, you'll notice it always equals 2

i.e (22-2)/10-0 = 20/10 = 2

or (14-2)/6-0 = 12/6 = 2

or even (22-8)/10-3 = 14/7 = 2

This means that m (slope) is 2.

Now as for b. b is the y intercept and that value occurs when x = 0. On the table, when x = 0 y = 2 so b = 2.

y = mx + b becomes

y = 2x + 2

6 0
3 years ago
7&gt;-4; subtract 7 from both sides
motikmotik

Answer:

The end result would be 0>-11

Step-by-step explanation:

Subtract 7 from each number and then just write it again.

7 - 7 = 0

-4 - 7 = -11

0>-11

5 0
3 years ago
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