Let the admission price for adults be 'x' and that of children be 'y'
Equation Formation.
2 x + 3 y = 80............equation(i)
3 x + y = 99.............equation(ii)
y = 99 - 3 x
2 x + 3(99 - 3 x) =80
2 x +297 - 9 x = 80
- 7 x = -217
x = 31
y = 99 - 3x
y = 99 - 3×31
y = 99 - 93
y = 6
Answer ⇒ Adults = $31
Children = $6
Answer:
-0.5, 2, 4.5, 7, 9.5
Step-by-step explanation:
The given terms are 6 apart, so the common difference is 1/6 of their difference:
d = (12 -(-3))/6 = 15/6 = 5/2 = 2.5
Add 2.5 to each term to get the next one. Then the sequence is ...
-3, <u>-0.5</u>, <u>2.0</u>, <u>4.5</u>, <u>7.0</u>, <u>9.5</u>, 12
So first distribute the 8 out then add everything together:
y-8y-96+4 = -7y-92
My guess is 6N but I’m not sure
X = smallest; x + 2 = middle, and x + 4 = largest
x + 2(x+2) = 20 + x + 4
x + 2x + 4=24 +x
3x + 4 = 24 + x
2x = 20
x = 10
so the three integers are 10, 12, and 14
