Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
Answer: 33.85 mm
Step-by-step explanation:
Use trigonometry, tan equation
You are give the tan angle and adjacent side, you need to find the opposite side so
O
T A
Tan(72)= x/11
x= tan(72) x 11
x= 33.85
Answer is 0.31. Hope this helps.
Answer:
(9/2)√x.
Step-by-step explanation:
Convert the radical to an exponent.
x√x = x^1 * x^1/2
= x^(1 + 1/2)
= x^3/2
So the derivative of 3x^3/2 is found as follows:
y' = 3 * 3/2x^(3/2 - 1)
= (9/2)x^1/2
= (9/2)√x.