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Nadya [2.5K]
3 years ago
6

1. Reflection across the x-axis. R(-2,2) ► R’ J(-1,4) ► J' G(3,4) ► G’

Mathematics
1 answer:
IgorC [24]3 years ago
7 0

reflection in the x axis

x,y=x-y

-2,2

2,-2

-1,4

1,-4

3,4

3,-4

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In the diagram, m ABC = 90° and the ratio x: y = 2 : 3 . Find the value of the larger angle.
faltersainse [42]

m ABC = 90° and the ratio x: y = 2 : 3

the value of the larger angle is 180⁰

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7 0
3 years ago
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Can u show me how to solve this problem 0.11 times 0.91
lisov135 [29]

Answer:

0.1001

Step-by-step explanation: Your answer is 0.1001

 0.91

 <u> 0.11</u>

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 0990

<u>00000</u>

0.1001


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3 years ago
Find the equation of the linear function represented by the table below in slope-intercept form.
Naily [24]

Question: Where is the y2? Please be more specific!

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3 years ago
Area of a Triangle
jek_recluse [69]

Answer:

3.51 (round to the nearest hundreds)

Step-by-step explanation:

PART A

slope of the line passing through AC : (6-1)/(1-2) = 5/-1 = -5

equation of the line passing through B and perpendicular to AC:

y-3 = 1/5(x-3)

y-3 = 1/5x -3/5

y = 1/5 x - 3/5 + 3

y = 1/5 x + (-3+15)/5

y = 1/5 x + 12/5

PART B

line that passes through the points A and C

y-1 = -5(x-2)

y = -5x+10 + 1

y = -5x + 11

Interception of the lines

y = 1/5x + 12/5

y = -5x + 11

-5x + 11 = 1/5x + 12/5

-25x +55 = x + 12

26x = 43

x = 43/26

y = -5(43/26) + 11

y= -215/26 + 11

y = (-215+286)/26 = 71/26

D (1.65, 2.73)

PART C

AC = \sqrt{(1-2)^2 + (6-1)^2} = \sqrt{1 + 25} = \sqrt{26} = 5,09902

BD = \sqrt{(3-1.65)^2 + (3-2.73)^2} = 1,376735

PART D

AREA = (5,09902 * 1.376735)/2 = 3,509999

8 0
3 years ago
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Effectus [21]

Answer:

The answer is x = -4/3

Step-by-step explanation:

5 0
3 years ago
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