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2 years ago

Solve the inequality. 2 divided by 5 is greater than or equal to x minus the quantity 4 divided by 5 end of quantity.

Mathematics

1 answer:

In-s [12.5K]2 years ago

7 0

2/5 ≥ x - (4/5). add 4/5 to each side
6/5 ≥ x

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A portion of John Locke's time card is shown below. How many hours did he work for the week?

Paraphin [41]

Answer:

Step-by-step explanation:

it's 8+8+8+7+9 so it's gonna be 40

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2 years ago

How many variable terms are in the expression 3x3y + 5x2 − 4y + z + 9? (Input a numeric value only.)

Anarel [89]

Answer:

Step-by-step explanation:

A variable term is a mathematical term in which a variable is by itself or is connected to a coefficient(s).

3x3y, 5x2, −4y, z.

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2 years ago

Helpp!! Pleaseeeeeeeeeeeeeee

weeeeeb [17]

Answer:

your answer is B i hope this helps :)

Step-by-step explanation:

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2 years ago

PLZ HELP I WILL GIVE THE BRAINLEST AND 22 PTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! An expression is shown below: 6(m + 2 +

n200080 [17]

Answer:

part A: expression 1: 6(8m+2)

expression 2: 6m+12+42m

Part B: 6(m+2+7m)= 6(8m+2)

combine like terms is 6(m+2+7m), so it is 6(2+8m) or 6(8m+2)

6(8m+2)= 6(8m+2)

Part C: 6m+12+42m=6(m+2+7m)

m=0

6(0+2+7(0))=6(0)+12+42(0)

6(2)= 12

12=12

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3 years ago

The amount of time Ricardo spends brushing his teeth follows a Normal distribution with unknown mean and standard deviation. Ric

Papessa [141]

Let $X$ denote the number of minutes spent brushing his teeth, and let $\mu$ be the mean and $\sigma$ the standard deviation for this distribution.

$\mathbb P(X$

The z-score corresponding to this probability is approximately $z=-0.2533$ , which means

$\dfrac{1-\mu}\sigma=-0.2533\iff\mu-0.2533\sigma=1$

Next, (note the sign change)

$\mathbb P(X>2)=0.02\implies\mathbb P(X\le2)=\mathbb P\left(\dfrac{X-\mu}\sigma\le\dfrac{2-\mu}\sigma\right)=0.98$

The corresponding z-score is approximately $z=2.0538$ , so you have

$\dfrac{2-\mu}\sigma=2.0538\iff\mu+2.0538\sigma=2$

Solving the two equations for $\mu$ and $\sigma$ , you'll find that the mean is approximately $\mu=1.1098$ and the standard deviation is approximately $\sigma=0.4334$ .

7 0

2 years ago