The horizontal distance to the control tower is approximately 18506.83m
Data;
- distance from the ground = 3900m
- angle of elevation = 11.4 degrees
- horizontal distance = ?
<h3>Trigonometric Ratio</h3>
To solve this problem, we need to use trigonometric ratio SOHCAHTOA.
In this case, we have the value of opposite and angle and we need to find the adjacent to the angle. The tangent of the angle would be perfect for this.
The horizontal distance to the control tower is approximately 18506.83m
Learn more on trigonometric ratio here;
brainly.com/question/4326804
Answer:
C, None of the above
Step-by-step explanation:
Step 1: Expand the brackets
-7 - 3(-4e-3)
-7 + 12e + 9
Step 2: Collect like terms
12e + 2
Because the answer is not a or b the answer is 'None of the Above'
Answer:
We accept H₀. We do not have argument to keep the claim that the mean breaking strength has increased
Step-by-step explanation:
Normal Distribution
Population Mean μ₀ = 1850 pounds
Standard Deviation σ = 90 pounds
Type of test
Null Hypothesis H₀ ⇒ μ = μ₀
Alternative Hypothesis Hₐ ⇒ μ > μ₀
A one tail test (right)
n = 21 as n < 30 we use t-student table
degree of fredom 20
t = 2.845
Sample mean μ = 1893
Then, we compute t statistics
t(s) = [ 1893 - 1850 ] / 90/ √n
t(s) = 43 * 4,583 / 90
t(s) = 197,069 / 90
t(s) = 2,190
And we compare t and t(s)
t(s) = 2.190
t = 2.845
Then t(s) < t
We are in the acceptance zone, we accept H₀
