Answer:
10650
Step-by-step explanation:
We are given the following expression:
![\sqrt[3]{875}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B875%7D)
We can factor 875 as:
![\sqrt[3]{125\times7}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%5Ctimes7%7D)
Now we will use the following property:
![\sqrt[x]{a\times b}=\sqrt[x]{a}\times\sqrt[x]{b}](https://tex.z-dn.net/?f=%5Csqrt%5Bx%5D%7Ba%5Ctimes%20b%7D%3D%5Csqrt%5Bx%5D%7Ba%7D%5Ctimes%5Csqrt%5Bx%5D%7Bb%7D)
Applying the property:
![\sqrt[3]{125}\times\sqrt[3]{7}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%5Ctimes%5Csqrt%5B3%5D%7B7%7D)
Solving the cubic root on the left:
![5\sqrt[3]{7}](https://tex.z-dn.net/?f=5%5Csqrt%5B3%5D%7B7%7D)
Since we get simplify any further this is the answer.
The equation describing the situation is given by
y - 0 = (5 - 0)/(47.5 - 0) (x - 0)
y = 5/47.5 x
y = 2/19 x
Therefore, it will require 19(11)/2 = 104.5 minutes to jog 11 miles.
Before cooling begins, the temperature of the water is 22°C.
Let the price of adult ticket and children ticket be a and c respectively
8a+5c=177.50 -> 24a+15c=532.5
12a+6c=255.00 -> 24a+12c=510
24a+15c-24a-12c=532.5-510
3c=22.5
c=7.5
a=17.5