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mart [117]
2 years ago
12

The tangent of the curve f(t) =2+nt+mt^2 at point (1,1/2) is parallel to the normal g(t)= t^2+6t+13(-2,2), calculate the values

m and n.​
Mathematics
1 answer:
Anettt [7]2 years ago
7 0

Step-by-step explanation:

The slope of g(t) as (-2,2) is given by

g'(t)=2t+6

g'(-2)=2(-2)+6=2

Since the normal is parallel to the tangent of f(t) at (1, 1/2),

The tangent line of f(t) has a slope of

\dfrac{d}{dx}f(t)=n+2mt=2

At point (1, 1/2), we know

f'(1)=n+2m=2

f(1)=2+n(1)+m(1)^2=2+n+m=\frac12

Solving,

n=5, m=-\frac72

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