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mart [117]
2 years ago
12

The tangent of the curve f(t) =2+nt+mt^2 at point (1,1/2) is parallel to the normal g(t)= t^2+6t+13(-2,2), calculate the values

m and n.​
Mathematics
1 answer:
Anettt [7]2 years ago
7 0

Step-by-step explanation:

The slope of g(t) as (-2,2) is given by

g'(t)=2t+6

g'(-2)=2(-2)+6=2

Since the normal is parallel to the tangent of f(t) at (1, 1/2),

The tangent line of f(t) has a slope of

\dfrac{d}{dx}f(t)=n+2mt=2

At point (1, 1/2), we know

f'(1)=n+2m=2

f(1)=2+n(1)+m(1)^2=2+n+m=\frac12

Solving,

n=5, m=-\frac72

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crimeas [40]

Answer:

a) X \sim Binom(n=16, p=0.2)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

The expected value is given by this formula:

E(X) = np=16*0.2=3.2

b) P(X=0)=(16C0)(0.2)^{0} (1-0.2)^{16-0}=0.02815

Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Part a

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=16, p=0.2)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

The expected value is given by this formula:

E(X) = np=16*0.2=3.2

Part b

For this case we want this probability:

P(X=0)

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And using this function we got:

P(X=0)=(16C0)(0.2)^{0} (1-0.2)^{16-0}=0.02815

6 0
3 years ago
What are 5 different equation that have x=5 as a solution.
777dan777 [17]
X+6=11
X-11=-6
5x=25
2x=10
2x+15=25

5 0
3 years ago
HELP!!BRAINLIEST AND 10 POINTS
leva [86]

Answer:

A

Step-by-step explanation:

I think that's da answer I hope it help ya

6 0
2 years ago
A line includes the points (8,-2) and (-8,-4). What is the slope intercept
VladimirAG [237]

Answer:

The equation of the line would be y = 1/8x - 3

Step-by-step explanation:

to find the slope intercept form of the line, you must first find the slope. You can do this using the slope formula.

m(slope) = (y2 - y1)/(x2 - x1)

m = (-2 - -4)/(8 - -8)

m = 2/16

m = 1/8

Then you can use this slope along with either point in point-slope form. Then solve for y.

y - y1 = m(x - x1)

y + 4 = 1/8(x + 8)

y + 4 = 1/8x + 1

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8 0
3 years ago
Marvin invested 65% of his retirement account in stocks and 35% in gold. Marvin believes that the return to stocks over the next
ser-zykov [4K]

Answer:

1)

the mean rate of return is 17 %

the standard deviation of return is 17.06055

2)

the probability that Marvin's portfolio will make at least 20% over the next 12 months is 0.4325

Step-by-step explanation:

Given the data in the question;

1)

For the portfolio, the mean return and standard deviation are computed as follows;

Mean = Return = 0.65 × 10 + 0.35 × 30

= 6.5 + 10.5

= 17 %

Therefore, the mean rate of return is 17 %

Standard deviation will be;

σp = √( 0.65² × 15² + 0.35² × 40² )

= √( 0.4225 × 225 + 0.1225 × 1600 )

= √( 95.0625 + 196 )  

= √291.0625

= 17.06055  

Therefore, the standard deviation of return is 17.06055

2)  

probability that Marvin's portfolio will make at least 20% over the next 12 months.

P( X > 20 )

we convert to a standard normal variable;

Z = \frac{20-17}{17.06055} )

Z = 0.17

from z table, p-value is;

p( X < 20 ) = 0.5675

P( X > 20 ) 1 - 0.5675  = 0.4325

Therefore, the probability that Marvin's portfolio will make at least 20% over the next 12 months is 0.4325

5 0
3 years ago
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