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3 years ago

3/5 + 3/7 = it a Fraction problem

2 answers:

5 0

<span>3/5 + 3/7
Multiply the denominator until they have the same common denominator.
21/35 + 15/35
Add the numerators but NOT the denominators
Final Answer: 36/35 or 1 1/35</span>

Paraphin [41]3 years ago

4 0

So first off you need common denominators. So what is eaiser for me, I just multiply 5*7. Which equals 35. Now you need to do that to the top. So you take 7*3 and 5*3. So then you would have 21/35+15/35. So then the answer is 36/35 simplified. 1 1/35

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The path of a model rocket can be represented by the equation h(t)=-t2+15t+16, where h(t) is the height, in feet, of the rocket

Musya8 [376]

The height is 52 feet.

Using t=3, we have:
-3² + 15(3) + 16 = -9 + 45 + 16 = 52

4 0

3 years ago

Read 2 more answers

How to write 3.05 in word form

Arturiano [62]

Three and five hundredths <span />

6 0

3 years ago

On an alien planet with no atmosphere, acceleration due to gravity is given by g = 12m/s^2. A cannonball is launched from the or

almond37 [142]

Answer:

a) $\vec r (t) = \left[(90\cdot \cos \theta)\cdot t \right]\cdot i + \left[(90\cdot \sin \theta)\cdot t -6\cdot t^{2} \right]\cdot j$ , b) $\theta = \frac{\pi}{4}$ , c) $y_{max} = 84.375\,m$ , $t = 3.75\,s$ .

Step-by-step explanation:

a) The function in terms of time and the inital angle measured from the horizontal is:

$\vec r (t) = [(v_{o}\cdot \cos \theta)\cdot t]\cdot i + \left[(v_{o}\cdot \sin \theta)\cdot t -\frac{1}{2}\cdot g \cdot t^{2} \right]\cdot j$

The particular expression for the cannonball is:

$\vec r (t) = \left[(90\cdot \cos \theta)\cdot t \right]\cdot i + \left[(90\cdot \sin \theta)\cdot t -6\cdot t^{2} \right]\cdot j$

b) The components of the position of the cannonball before hitting the ground is:

$x = (90\cdot \cos \theta)\cdot t$

$0 = 90\cdot \sin \theta - 6\cdot t$

After a quick substitution and some algebraic and trigonometric handling, the following expression is found:

$0 = 90\cdot \sin \theta - 6\cdot \left(\frac{x}{90\cdot \cos \theta} \right)$

$0 = 8100\cdot \sin \theta \cdot \cos \theta - 6\cdot x$

$0 = 4050\cdot \sin 2\theta - 6\cdot x$

$6\cdot x = 4050\cdot \sin 2\theta$

$x = 675\cdot \sin 2\theta$

The angle for a maximum horizontal distance is determined by deriving the function, equalizing the resulting formula to zero and finding the angle:

$\frac{dx}{d\theta} = 1350\cdot \cos 2\theta$

$1350\cdot \cos 2\theta = 0$

$\cos 2\theta = 0$

$2\theta = \frac{\pi}{2}$

$\theta = \frac{\pi}{4}$

Now, it is required to demonstrate that critical point leads to a maximum. The second derivative is:

$\frac{d^{2}x}{d\theta^{2}} = -2700\cdot \sin 2\theta$

$\frac{d^{2}x}{d\theta^{2}} = -2700$

Which demonstrates the existence of the maximum associated with the critical point found before.

c) The equation for the vertical component of position is:

$y = 45\cdot t - 6\cdot t^{2}$

The maximum height can be found by deriving the previous expression, which is equalized to zero and critical values are found afterwards:

$\frac{dy}{dt} = 45 - 12\cdot t$

$45-12\cdot t = 0$

$t = \frac{45}{12}$

$t = 3.75\,s$

Now, the second derivative is used to check if such solution leads to a maximum:

$\frac{d^{2}y}{dt^{2}} = -12$

Which demonstrates the assumption.

The maximum height reached by the cannonball is:

$y_{max} = 45\cdot (3.75\,s)-6\cdot (3.75\,s)^{2}$

$y_{max} = 84.375\,m$

7 0

3 years ago

Mildred has three little girls, Margo, Delilah, and Gertrude. If she randomly chooses one of them to clean the kitchen after din

seropon [69]

1/3 let me know if I’m right

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3 years ago

How do you solve this equation log(3x+1)=5

Len [333]

$log_{10} 3x+1=5$

$3x+1=10^5$

$3x+1=100000$

$3x=99999$

$x=333333$

Just remember that in the form of $log_ab=x$ , you get $a^x=b$ .

7 0

3 years ago

Read 2 more answers