First of all, division is the opposite of multiplication. So if I
divide 72 by 3 I should get 24, since 3*24 = 72.
![\bf f(x)=x^2+4x\qquad \cfrac{df}{dx}=2x+4\qquad \boxed{f''(x)=2}\impliedby \begin{array}{llll} \textit{just a positive}\\ constant \end{array}](https://tex.z-dn.net/?f=%5Cbf%20f%28x%29%3Dx%5E2%2B4x%5Cqquad%20%5Ccfrac%7Bdf%7D%7Bdx%7D%3D2x%2B4%5Cqquad%20%5Cboxed%7Bf%27%27%28x%29%3D2%7D%5Cimpliedby%20%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A%5Ctextit%7Bjust%20a%20positive%7D%5C%5C%0Aconstant%0A%5Cend%7Barray%7D)
there are no inflection points, because it never changes concavity, is just a constant and thus for any region over the x-axis, will always be a positive value, and thus is always "concave up".
Answer:
75
Step-by-step explanation:
70, 72, 77, 80, 81: median is 77
x+77/2=76
x=75
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The first choice can be any one of the 8 side dishes.
For each of these . . .
The 2nd choice can be any one of the remaining 7.
Total number of ways to pick 2 out of 8 = (8 x 7) = 56 ways .
BUT ...
That doesn't mean you can get 56 different sets of 2 side dishes.
For each different pair, there are 2 ways to choose them . . .
(first A then B), and (first B then A). Either way, you wind up with (A and B).
So yes, there are 56 different 'WAYS' to choose 2 out of 8.
But there are only 28 different possible results, and 2 'ways'
to get each result.