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bija089 [108]
3 years ago
15

What's the concavity of f(x)=x^2+4x

Mathematics
1 answer:
Anna71 [15]3 years ago
8 0
\bf f(x)=x^2+4x\qquad \cfrac{df}{dx}=2x+4\qquad \boxed{f''(x)=2}\impliedby 
\begin{array}{llll}
\textit{just a positive}\\
constant
\end{array}

there are no inflection points, because it never changes concavity, is just a constant and thus for any region over the x-axis, will always be a positive value, and thus is always "concave up".
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