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tensa zangetsu [6.8K]
3 years ago
13

Evaluate 5k + 1 when: *

Mathematics
1 answer:
wlad13 [49]3 years ago
5 0

1

k^2 = 4k

k = 0, k = 4

#2

k^2 - 5k = k + 7

k^2 - 6k = 7

k^2 - 6k + 9 = 16

k - 3 = 4 ⇒ k = 7

k - 3 = -4 ⇒ k = -1

#3

k^3 - 5k^2 + 3k = -k

k^3 - 5k^2 + 4k = 0

k(k^2 - 5k + 4) = 0

k = 0, k = 1, k = 4

#4

|k + 1| + 2 = 8

|k + 1| = 6

k = 5, k = -7

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The sector COB is cut from the circle with center O. The ratio of the area of the sector removed from the whole circle to the ar
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Answer:

Ratio = \frac{R^2 - r^2 }{ r^2}

Step-by-step explanation:

Given

See attachment for circles

Required

Ratio of the outer sector to inner sector

The area of a sector is:

Area = \frac{\theta}{360}\pi r^2

For the inner circle

r \to radius

The sector of the inner circle has the following area

A_1 = \frac{\theta}{360}\pi r^2

For the whole circle

R \to Radius

The sector of the outer sector has the following area

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Cancel out common factor

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Express as fraction

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