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3 years ago

B. 4a’(a? – b?) and 9a’(a? – bº) LCM of this expression

Mathematics

2 answers:

Feliz [49]3 years ago

8 0

Answer:

Answer:

Step-by-step explanation:

1st expression:4a(a-b)

2nd expression:9a(a-b)

So L.C.M=a(a-b)4×9

=36a^2-36ab

GuDViN [60]3 years ago

4 0

I got same answer ^^^ of this one

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Find all the zeros of the equation x^4-6x^2-7x-6=0

rusak2 [61]

Answer:

The zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Step-by-step explanation:

We have been given the equation x^4-6x^2-7x-6=0

Use rational root theorem, we have

$a_0=6,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:3,\:6,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:3,\:6}{1}$

$-\frac{2}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+2$

$=\left(x+2\right)\frac{x^4-6x^2-7x-6}{x+2}\\$

$=x^3-2x^2-2x-3$

Again factor using the rational root test, we get

$=\left(x+2\right)\left(x-3\right)\left(x^2+x+1\right)$

Using the zero product rule, we have

$x+2=0:\quad x=-2\\x-3=0:\quad x=3\\x^2+x+1=0\\\\x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\\\=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Therefore, the zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

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Answer:

Step-by-step explanation:

8x - 6 > 12 + 2x

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6x -6 > 12

Add 6 to each side

6x -6+6 > 12+6

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Divide by 6

6x/6 > 18/6

x > 3

The only value greater than 3 is 5

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Solve for x, rounding to the nearest hundredth.<br> 10^3x = 98

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Answer:

see explanation

Step-by-step explanation:

10^3x=98

1000x=98

x=98/1000

x=49/500

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if it is rounded to the nearest hundredth then x=0

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Answer:

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Equal sets have the exact same elements, so they must have the same number of elements. Therefore, equal sets must also be equivalent. No, not all equivalent sets are also equal sets

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3 years ago

B. 4a’(a? – b?) and 9a’(a? – bº) LCM of this expression​

B. 4a’(a? – b?) and 9a’(a? – bº) LCM of this expression