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kirza4 [7]
3 years ago
11

B. 4a’(a? – b?) and 9a’(a? – bº) LCM of this expression​

Mathematics
2 answers:
Feliz [49]3 years ago
8 0

Answer:

Answer:

Step-by-step explanation:

1st expression:4a(a-b)

2nd expression:9a(a-b)

So L.C.M=a(a-b)4×9

=36a^2-36ab

GuDViN [60]3 years ago
4 0
I got same answer ^^^ of this one
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Answer:

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nataly862011 [7]

Answer:

m\angle QSN=65^\circ

Step-by-step explanation:

In the given figure, PQRS is a rhombus and SRM is an equilateral triangle.

We are also given that SN⊥RM and that ∠PRS = 55°.

And we want to find the measure of ∠QSN.

Remember that since PQRS is a rhombus, the angles formed by its diagonals are right angles. Let the intersection point of the diagonals be K. Therefore:

m\angle RKS=90^\circ

Now, RKS is also a triangle. The interior angles of all triangles must be 180. Thus:

m\angle RKS+m\angle KSR+m\angle SRK=180

Substitute in known values:

90+55+m\angle KSR=180

Solve for ∠KSR:

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Since SRM is an equilateral triangle, this means that:

m\angle SRM=m\angle RMS=m\angle MSR=60^\circ

Note that RNS is also a triangle. Therefore:

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∠QSN is the addition of the two angles:

m\angle QSN=m\angle KSR+m\angle NSR

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