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nalin [4]
2 years ago
8

13 - (n • 6) = 50 Pls help what would be the equation

Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
5 0

Answer:

n=-17/3

Step-by-step explanation:

16-(n.6)=50

16-6n=50

-6n=34

n=34/-6

n=-17/3

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At South High School, 37% of the teachers are between 22 and 30 years old, 25% are between 31 and 40
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I don’t know but I’m not gonna say anything so you don’t get it wrong
6 0
2 years ago
Write an informal proof to show triangles ABC and DEF are similar. Please don’t answer if you don’t know!!
Mila [183]

Answer:

ΔABC ~ ΔDEF

Step-by-step explanation:

If the given triangles ΔABC and ΔDEF are similar,

Their corresponding sides will be proportional.

\frac{\text{AB}}{\text{DE}}=\frac{\text{BC}}{\text{EF}}=\frac{\text{AC}}{\text{DF}}

By substituting the measures of the given sides,

\frac{4}{2}=\frac{6}{3}=\frac{2}{1}

2 = 2 = 2

Since, corresponding sides of both the triangles are proportional, both the triangles will be similar.

ΔABC ~ ΔDEF

8 0
3 years ago
A. Incorrect; the student should add 8 + 2 to calculate the x-coordinate and should add 5 + 9 to calculate the y-coordinate. B.
likoan [24]

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A

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I think it’s a based on what you given

3 0
2 years ago
True or False!!!! The measure of a tangent-tangent angle is twice the difference of the measures of the intercepted arcs.
lozanna [386]

answer : False

The measure of a tangent-tangent angle is one - half the difference of the measures of the intercepted arcs.

The diagram is attached below

AB  and BC are the two tangents

By exterior angle theorem

 ∠3 = ∠2 + ∠4

So   ∠2 = ∠3 - ∠4

Now we find angle 3  and 4, we know when a chord and tangent intersect at a point then the measure of angle is one half of measure of intercepted arc

∠3 = \frac{1}{2} * arc(ADC)

∠4 = \frac{1}{2} * arc(AC)

 ∠2 = ∠3 - ∠4

 ∠2 = \frac{1}{2} * arc(ADC)  -  \frac{1}{2} * arc(AC)

∠2 = \frac{1}{2} ( arc(ADC) - arc(AC))

The measure of a tangent-tangent angle is one half the difference of the measures of the intercepted arcs.



7 0
3 years ago
Is it possible for a line to pass through only one quadrant?<br> How about four quadrants? explain
neonofarm [45]
Yes it is possible for a line to only start in one quadrant and never leave that quadrant and vice versa a line can start in one quadrant and pass into another quadrant but how will you know if you line will be in certain or multiple quadrants simple just look at your points given if you have the points (3,4) (4,5) you notice that your X's are positive and your Y's are positive there is only one quadrant were your X and Y are positive and that is quadrant 1 but lets say you have points (-4,5),(3,4) you see how one of the points have a negative X and a positive Y there is only one quadrant that has a negative X and a positive Y that is quadrant 2 and and for point (3,4) that is in quadrant 1 so your line will run through quadrant 2 and 1 

yes it is possible for a line to only be in one quadrant and it is also possible for a line to be in multiple quadrants basically it can be any place on a plane  
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8 0
3 years ago
Read 2 more answers
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