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masya89 [10]
3 years ago
11

1) (7 X 6) = 2 [{45 - 3(7 X 2 - 15 + 6)} + 4] ​

Mathematics
2 answers:
zhuklara [117]3 years ago
7 0

Answer:

42=2[{45-3(14-21)}+4]

42=2[{45-3×-6}+4]

42=2[{45-18}+4]

42=2[{27}+4]

42=2[27+4]

42=2×31

42=62

pogonyaev3 years ago
7 0

Answer:

1) (7 X 6) = 2 [{45 - 3(7 X 2 - 15 + 6)} + 4]

or,42=2[{45-3(14-15+6)}+4]

or,42=2[{45-3(14-21)}+4]

or,42=2[{45-3X(-7)}+4]

or,42=2[45+21}+4]

or,42=2X70

:42=140

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What is the value of x in the figure?<br><br> Enter your answer in the box
Tcecarenko [31]

Answer:

x =68

Step-by-step explanation:

We know that x+22 = 90 because the sum of the two angles is a vertical angle to the right angle and vertical angles are equal.


x+22 =90

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3 0
3 years ago
What is the sum of forty-six and ninety-four?
lbvjy [14]

Answer:

140

Step-by-step explanation:

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8 0
3 years ago
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What is 46.3 minus 44.58 (tell me how you got it step by step please!)
LUCKY_DIMON [66]

46.3 - 44.58 \\  =1.72

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3 years ago
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 Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III
Paha777 [63]

Given:

\sin x=-\dfrac{15}{17}

x lies in the III quadrant.

To find:

The values of \sin 2x, \cos 2x, \tan 2x.

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others  are negative.

We know that,

\sin^2 x+\cos^2 x=1

(-\dfrac{15}{17})^2+\cos^2 x=1

\cos^2 x=1-\dfrac{225}{289}

\cos x=\pm\sqrt{\dfrac{289-225}{289}}

x lies in the III quadrant. So,

\cos x=-\sqrt{\dfrac{64}{289}}

\cos x=-\dfrac{8}{17}

Now,

\sin 2x=2\sin x\cos x

\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})

\sin 2x=-\dfrac{240}{289}

We know that,

\cos 2x=1-2\sin^2x

\cos 2x=1-2(-\dfrac{15}{17})^2

\cos 2x=1-2(\dfrac{225}{289})

\cos 2x=\dfrac{289-450}{289}

\cos 2x=-\dfrac{161}{289}

Using the trigonometric ratios, we get

\tan 2x=\dfrac{\sin 2x}{\cos 2x}

\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}

\tan 2x=\dfrac{240}{161}

Hence, the required values are \sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}.

6 0
3 years ago
The population of birds in a sanctuary increases at a steady rate. The graph of the population over time has the points (1, 105)
Oksanka [162]
(1,105),(3,315)
slope = (315 - 105) / (3 - 1) = 210/2 = 105

y = mx + b
slope(m) = 105
use either of ur points....(1,105)...x = 1 and y = 105
now we sub and find b, the y int
105 = 1(105) + b
105 = 105 + b
105 - 105 = b
0 = b
so ur equation is : y = 105x + 0 which can be written as y = 105x

now to find a point on the line, sub in any number for x and solve for y
y = 105x....subbing in 2 for x
y = 105(2)
y = 210....so another point on the line is (2,210).....thats just one point, u can find more if u want....just sub in any number for x and solve for y
5 0
3 years ago
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