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Rudik [331]
3 years ago
10

There are 8 rows of tulips there are 5 rows of roses how much is it all together

Mathematics
1 answer:
Papessa [141]3 years ago
3 0

Answer:

40 all together

Step-by-step explanation:

1. 8 rows of tulips and 5 rows of roses

2. 8*5=40

3. There are 40 flowers all together

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Use substitution to solve each system of equations.<br><br>x-2y<br>y=x-2​
Helga [31]

Answer:

-x+4

Step-by-step explanation:

x-2y

y= x-2

x-2(x-2)

x-2x+4

-x+4

3 0
4 years ago
The shipping cost for order at an online store is 1/10 the cost of the items you order. What is an expression for the total cost
Katen [24]

Answer:

B. $79 + 0.1($79)

Step-by-step explanation:

Given that;

the shipping cost for an order = 1/10 multiply by the cost of the items bought;

i.e.  \dfrac{1}{10}\times x

where

x = cost of items ordered for.

This implies that:

\implies x + 0.1x

The objective is to determine the expression for the total cost of an order which is $79

x = 79

Then,  the total cost of an order is

$79 + 0.1($79)

4 0
3 years ago
The surface area 5cm x 14cm x 6cm
Rom4ik [11]
The surface is the sun of all the sides. With the information provide I can only work out the volume, which is 420cm^3
4 0
3 years ago
(98 Points) Steven wants to buy a $250 computer. He has a coupon that he wants to use when he buys the computer. Steven jots dow
Andrei [34K]

Answer:

x=.83

Step-by-step explanation:

What you do is you have to get x by itself.

You will have to divide 250 on both sides to get x by itself.

x=.83 is your answer.

6 0
4 years ago
Read 2 more answers
I am confused on numbers 25 and 29, the instructions are at the top.
kvasek [131]
#25 is fairly simple.  Plug in -4 and 3 into the equation, and the extraneous root will be the one that does not work.
\sqrt{12-(-4)} =  \sqrt{16} =  \frac{+}{}4
Extraneous root in this case is positive four since +4≠-4
<span>\sqrt{12-3} = \sqrt{9} = \frac{+}{}3
</span>In this case it's negative 3, since -3≠3

#29 can be turned into a quadratic equation.
x= \sqrt{2x+3}
Square both sides to get
x^{2}=2x+3
Then bring the 2x+3 to the other side, setting the quadratic equal to zero.
x^{2}-2x-3=0
Factor to find that it's equivalent to
(x-3)(x+1)=0
Therefore x is equal to positive 3 and negative 1.  Plug both back into the original equation.  Whichever does not work is the extraneous root, and the answer is the one that does.
<span>x= \sqrt{2x+3}
</span><span>3= \sqrt{2(3)+3}
</span><span>3= \sqrt{9}
</span>Extraneous root would be negative 3.

<span>-1= \sqrt{2(-1)+3}
</span><span>-1= \sqrt{1}
</span>Extraneous root would be positive 1.

Your answers are positive 3 and negative 1.
Extraneous roots are negative 3 and positive 1.
3 0
3 years ago
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