Please Help Me I really need Accurate answer Can anyone help me?

What is the distance between the lines y = 2x and y = 2x+5? Round your answer to the nearest tenth.

The distance between both lines is 2.24 units

Step-by-step explanation:

There is no straight method to find the distance between two lines. The distance can be found out by finding a point on one line and then finding the distance of that point from the other line. The y-coordinate of point is obtained by putting any value of x in equation . The x and y combined give us the point.

Given

$y=2x\\Putting\ x=1\\y=2(1)\\y=2\\So, the\ point\ on\ y=2x\ is\ (1,2)$

We have to find the distance of this point from y=2x+5

$y=2x+5\\Subtracting\ y\ from\ both\ sides\\y-y=2x+5-y\\2x-y+5=0$

The formula for finding distance of a point (x,y) from a line is:

$d=\frac{|Ax+By+C|}{\sqrt{A^2+B^2}}$

A=2

B=-1

C=5

Putting the values in the formula

$d=\frac{|(2)(1)+(-1)(2)+5|}{\sqrt{(2)^2+(-1)^2}}\\d=\frac{|2-2+5|}{\sqrt{4+1}}\\d=\frac{|5|}{\sqrt{5}}\\d=\frac{5}{\sqrt{5}}\\d=2.236\ units$

Rounding off will give: 2.24 units

The distance between both lines is 2.24 units

Keywords: Equations of lines

Learn more about distance in lines at:

#LearnwithBrainly

7 0

2 years ago

se vendieron 144 boletos. 2 pesos por adulto y un peso por niño, si se gastaron 207 pesos cuantos boletos de adulto se vendieron

natulia [17]

Answer:

Se vendieron 81 boletos de niños y 63 boletos de adultos.

Step-by-step explanation:

La cantidad de boletos vendidos es igual a:

$144 = a + n$ (1)

En donde a es por adultos y n por niños

A su vez, el dinero gastado equivale:

$207 = 2*a + 1*n$ (2)

Resolviendo la ecuación (1) para a:

$a = 144 - n$ (3)

Introduciendo (3) en la ecuación (2) tenemos:

$207 = 2*(144 - n) + n$

$n = 81$

Ahora podemos calcular el numero de boletos de adultos vendidos introduciendo n en la ecuación (3):

$a = 144 - n = 144 - 81 = 63$

Entonces, se vendieron 81 boletos de niños y 63 boletos de adultos.

Espero que te sea de utilidad!

5 0

2 years ago

8p + 2q = -16 2p - q=2

yKpoI14uk [10]

Answer:

p = -1 q = -4

Step-by-step explanation:

a system of eq and solve for p and q ??? can do :)

Eq. 1) 8p + 2q = - 16

Eq. 2) 2p - q = 2

use Eq .2 and solve for q

2p - 2 = q

plug into Eq.1 with q

8p +2(2p - 2) = - 16

8p +4p -4 = -16

12p = - 12

p = -1

plug -1 into Eq. 1 for p and solve for q

8(-1) + 2q = - 16

-8 + 2q = - 16

2q = -8

q = -4

8 0

2 years ago

R^3 +4r^2-25r-100 Help

Marina86 [1]

Answer:

The zeroes in this equation are -5, -4, and 5

Step-by-step explanation:

In order to find these, you need to factor by splitting. For this, we separate out the two halves of the equation and pull out the greatest common factor of each. Let's start with the front end.

r^3 + 4r^2

r^2(r + 4)

Now the second half.

-25r - 100

-25(r + 4)

Since what is left in the parenthesis are exactly the same, we can use that parenthesis next to one with what we pulled out.

(r^2 - 25)(r + 4)

And we can further factor the first parenthesis using the difference of two squares

(r^2 - 25)(r + 4)

(r + 5)(r - 5)(r + 4)

Now that we are fully factored, set each parenthesis equal to 0 and solve for x.

r + 5 = 0

r = -5

r - 5 = 0

r = 5

r + 4 = 0

r = -4

7 0

2 years ago

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0

2 years ago

Please Help Me I really need Accurate answer Can anyone help me?​

Please Help Me I really need Accurate answer Can anyone help me?