Answer:
for the last u have to..
Step-by-step explanation:
choose the one
Answer: Y = -7
Step-by-step explanation:
what you need to do is plug in the X-imput into the exponential slot that has the tiny X.
your answer is "C"
thanks! :)
Answer:
![-2y^{b-1}](https://tex.z-dn.net/?f=-2y%5E%7Bb-1%7D)
Step-by-step explanation:
![\frac{12x^ay^b}{-6x^ay}](https://tex.z-dn.net/?f=%5Cfrac%7B12x%5Eay%5Eb%7D%7B-6x%5Eay%7D)
In multiplication of fractions you can do this:
.
So that is exactly what we are going to do here:
![\frac{12x^ay^b}{-6x^ay}](https://tex.z-dn.net/?f=%5Cfrac%7B12x%5Eay%5Eb%7D%7B-6x%5Eay%7D)
![\frac{12}{-6} \cdot \frac{x^a}{x^a} \cdot \frac{y^b}{y}](https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7B-6%7D%20%5Ccdot%20%5Cfrac%7Bx%5Ea%7D%7Bx%5Ea%7D%20%5Ccdot%20%5Cfrac%7By%5Eb%7D%7By%7D)
We know that 12 divided by -6=12/-6 =-2.
We also know assuming x isn't 0 that x^a/x^a=1.
On the last fraction, the only thing you can do there to simplify is use the following law of exponents:
.
So we have
![\frac{12x^ay^b}{-6x^ay}](https://tex.z-dn.net/?f=%5Cfrac%7B12x%5Eay%5Eb%7D%7B-6x%5Eay%7D)
![\frac{12}{-6} \cdot \frac{x^a}{x^a} \cdot \frac{y^b}{y}](https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7B-6%7D%20%5Ccdot%20%5Cfrac%7Bx%5Ea%7D%7Bx%5Ea%7D%20%5Ccdot%20%5Cfrac%7By%5Eb%7D%7By%7D)
![(-2) \cdot (1) \cdot (y^{b-1})](https://tex.z-dn.net/?f=%28-2%29%20%5Ccdot%20%281%29%20%5Ccdot%20%28y%5E%7Bb-1%7D%29)
Simplifying a bit and leaving out the ( ).
![-2y^{b-1}](https://tex.z-dn.net/?f=-2y%5E%7Bb-1%7D)