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alisha [4.7K]
3 years ago
13

A mystery number rounds to 200 when rounded to nearest hundred. The sum of its ditgits is 10. When rounded to the nearest 10, it

rounds to a number whose digits have a sum of 5. What is the mystery number
Mathematics
1 answer:
9966 [12]3 years ago
7 0

Step-byiioiiiiiioiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

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The temperature at 6.00 am was - 12 the temperature increased by 1/2 each hour for 6 hours what was the temperature in degrees F
Illusion [34]

Answer: -9 degrees Fahrenheit

Step-by-step explanation:

Given: Temperature at 6:00 AM = -12 degrees Fahrenheit

Temperature increased each hour = \dfrac12 degrees Fahrenheit

Temperature increase in 6 hours = 6\times\dfrac12=3\text{ degrees Fahrenheit}

Temperature at noon = Temperature at 6:00 AM+Temperature increase in 6 hours

= -12+3 degrees Fahrenheit

= -9 degrees Fahrenheit

Hence, the temperature in degrees Fahrenheit at noon= -9 degrees Fahrenheit

8 0
3 years ago
Consider the equation 4x + 1 = 2x + 5
Darya [45]

(a) Without solving the equation we can't determine whether its true or false.

(b) If x = 3

4x + 1 = 2x + 5

4(3) + 1 = 2(3) + 5

12 + 1 = 15 + 5

13 = 20

No, if x = 3, the equation will not be true.

(c) 4x + 1 = 2x + 5

4x - 2x = 5 - 1

2x = 4

x = 4/2

x = 2

This shows that x = 2 makes the equation true.

8 0
3 years ago
What do you think makes a relation a function or not a function?
never [62]

Answer:

A relation is a function if... none of the x terms repeat. The y terms don't matter.

5 0
2 years ago
The price for certain produce items at Greg's local supermarket are
Vaselesa [24]
72.28 i took the test it was easy bro
8 0
3 years ago
Which are the solutions of the quadratic equation x^2=-5x-3
frutty [35]
The correct answer would be \frac{-5 +/-  \sqrt{13} }{2}

In order to solve for this you must first get the equation equal to 0. 

<span>x^2=-5x-3 ----> add 5x to both sides. 
x^2 + 5x = -3 ----> add 3 to both sides.
x^2 + 5x + 3 = 0

Now knowing this we can use the coefficients of each one in descending order of power as a, b and c. 

a = 1 (because it is the coefficient to x^2)
b = 5</span> (because it is the coefficient to x)
c = 3 (because it is the end number)

Now we can plug these values into the quadratic equation. 

\frac{-b +/-  \sqrt{b^{2} - 4ac } }{2a}

\frac{-5 +/- \sqrt{5^{2} - 4(3)(1) } }{2(1)}

\frac{-5 +/- \sqrt{13} }{2}

And those would be your two answers.
5 0
3 years ago
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