Answer:
Option A
Step-by-step explanation:
The complete question is attached here
The rate of increase of bacterial population be K
As we know

where Y is the final population. In this case it is 1000
K is the rate of increase of population i.e 3 times per hour
T is the time in hours
Y0 is the initial population = 5
Substituting the given values, we get -

Taking log on both sides, we get -
ln
= ln 

T = 2.084 hours
hence, option A is correct
Answer:
Step-by-step explanation:
For Question 3, we are simply taking an input for the function, as a value of x and solving the equation. For part a, we substitute 3/14 into the first function, and solve it:
f(x) = 7(3/14) + 2
f(x) = 21/14 + 2
f(x) = 49/14
f(x) = 7/2
For part b, we take the input of -3 into the second function and solve the equation:
h(x) = 4(-3)^2
h(x) = 4(9)
h(x) = 36
For Question 4, we are simply solving this equation by isolating the x variable. First, we simplify the equation to 4-5x+15+2x = -2 and simplify this again to -3x+19 = -2. Now, we can subtract 19 from both sides of the equation to get -3x = -21. Lastly, we isolate the x variable by dividing both sides of this equation by -3, to get x = 7.
Answer:
<u>x = 60°</u>
Step-by-step explanation:
The rest of the question is the attached figure.
And it is required to find the angle x.
As shown, a rhombus inside a regular hexagon.
The regular hexagon have 6 congruent angles, and the sum of the interior angles is 720°
So, the measure of one angle of the regular hexagon = 720/6 = 120°
The rhombus have 2 obtuse angles and 2 acute angles.
one of the obtuse angles of the rhombus is the same angle of the regular hexagon.
So, the measure of each acute angle of the rhombus = 180 - 120 = 60°
So, the measure of each acute angle of the rhombus + the measure of angle x = the measure of one angle of the regular hexagon.
So,
60 + x = 120
x = 120 - 60 = 60°
<u>So, the measure of the angle x = 60°</u>
Complete Question
Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n=150
Answer:
Normal sampling distribution can not be used
Step-by-step explanation:
From the question we are told that
The null hypothesis is 
The alternative hypothesis is 
The sample size is n= 150
Generally in order to use normal sampling distribution
The value 
So


Given that
normal sampling distribution can not be used
Answer:
A
Step-by-step explanation:
you will get 3(x-1)×(x+1) you can get the 3 and x by itself then it would be x+3