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andrew11 [14]
3 years ago
8

7x-2=61 how to solve

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
6 0
7x - 2 = 61    |add 2 to both sides

7x = 63    |divide both sides by 7

x = 9
Maurinko [17]3 years ago
3 0
7x-2=61
7x= 61+2
7x=63
7/7=63/7
x=9
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The line graph below shows how Fergus has done on the first five vocabulary quizzes of the semester. What was Fergus's second-hi
RSB [31]
D) 85% is your answer

Look at The "Scores" (y-axis)

the second to highest dot was located on the 85% point.

Therefore, D) is your answer


hope this helps
7 0
3 years ago
The accompanying data represent the daily​ (for example, Monday to​ Tuesday) movement of Johnson​ & Johnson​ (JNJ) stock for
egoroff_w [7]

Supposing that the stock increases in 37 days, the 95% confidence interval for the proportion of days JMJ stock increases is: (0.484, 0.7292)

  • The lower bound is of 0.484.
  • The upper bound is of 0.7292.
  • The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

Supposing that it increases on 37 out of 61 days:

n = 61, \pi = \frac{37}{61} = 0.6066

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 - 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.484

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 + 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.7292

The ​95% confidence interval for the proportion of days JMJ stock increases is (0.484, 0.7292), in which 0.484 is the lower bound and 0.7292 is the upper bound.

The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>

A similar problem is given at brainly.com/question/16807970

4 0
2 years ago
Since opening night, attendance at Play A has increased steadily, while attendance at Play B first rose and then fell. Equations
Y_Kistochka [10]

Answer:

On 5th day and 13th day Attendance was equal for both plays and it was

231 for each .

Step-by-step explanation:

In order to find same attendance ,we need  plug both equation equal

         -x^2+26x+126 = 8x+191

        -x^2+26x-8x+126-191 = 0

        -x^2 +18x-65 =0

      multiplying both sides by -1 ,we get

      x^2 -18x+ 65 =0

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         x =5 and x =13

On 5th day and 13th  day attendance was same.

And attendance can be obtained by plugging x =5 in either of equation

 y = 8(5)+191

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8 0
3 years ago
Need help with math work
gizmo_the_mogwai [7]
Plug in x = 12 and y = -5 into the given equation:-

3(12) - 3(-5) = 36 + 15 = 51  Not 21

So (12,-5) is not a solution.
4 0
3 years ago
Read 2 more answers
The set of integers greater than 50
UkoKoshka [18]
The set of integers greater than 50 are (51,52,53,54...)
5 0
3 years ago
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