Question

Factorize 2x^2-5/3xy-2y^2

Answer 1

Answer:

$y = 0 \: .x = \frac{2}{3} y$

Step-by-step explanation:

$\frac{2 {x}^{2} - 5 }{3xy - 2 {y}^{2} }$

$3xy - 2 {y}^{2} = 0$

$y \times (3x - 2y) = 0$

$y = 0 = 3x - 2y = 0$

$y = 0 = 3x = 2y$

$y = 0$

$x = \frac{2}{3} y$

$y = 0. \: x = \frac{2}{3} y$

Answer 2

I hope it helps you