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3 years ago

Can somebody help please A. 110,acute B. 135,obtuse C.125,obtuse D.55,acute

Mathematics

2 answers:

ElenaW [278]3 years ago

4 0

Answer:

125 acute

Step-by-step explanation:

look at the line on the number for the angle

hodyreva [135]3 years ago

3 0

Answer:

Step-by-step explanation:

I Think do to the way U shows looks like 135

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What is the population in 2020 of a place that has a population of 4 million people in 2011 and is growing at a rate of 1.3%?

Stolb23 [73]

Answer:

370 million

Step-by-step explanation:

In the 10 years from 2000 to 2010, the population was multiplied by the factor ...

100% + 9.6% = 109.6% = 1.096

In the next 20 years from 2010 to 2030, the population will be multiplied by that factor twice, if it grows at the same rate:

2030 population = (308 million)·(1.096²) ≈ 370 million

5 0

3 years ago

Find the projection of the vector A = î - 2ġ + k on the vector B = 4 i - 4ſ + 7k. 15. Given the vectors A = 2 i +3 ſ +6k and B =

Gwar [14]

Answer:

Part 1)

Projection of vector A on vector B equals 19 units

Part 2)

Projection of vector B' on vector A' equals 35 units

Step-by-step explanation:

For 2 vectors A and B the projection of A on B is given by the vector dot product of vector A and B

Given

$\overrightarrow{v_{a}}=\widehat{i}-2\widehat{j}+\widehat{k}$

Similarly vector B is written as

$\overrightarrow{v_{b}}=4\widehat{i}-4\widehat{j}+7\widehat{k}$

Thus the vector dot product of the 2 vectors is obtained as

$\overrightarrow{v_{a}}\cdot \overrightarrow{v_{b}}=(\widehat{i}-2\widehat{j}+\widehat{k})\cdot (4\widehat{i}-4\widehat{j}+7\widehat{k})\\\\\overrightarrow{v_{a}}\cdot \overrightarrow{v_{b}}=1\cdot 4+2\cdot 4+1\cdot 7=19$

Part 2)

Given vector A' as

$\overrightarrow{v_{a'}}=2\widehat{i}+3\widehat{j}+6\widehat{k}$

Similarly vector B' is written as

$\overrightarrow{v_{b'}}=\widehat{i}+5\widehat{j}+3\widehat{k}$

Thus the vector dot product of the 2 vectors is obtained as

$\overrightarrow{v_{b'}}\cdot \overrightarrow{v_{a'}}=(\widehat{i}+5\widehat{j}+3\widehat{k})\cdot (2\widehat{i}+3\widehat{j}+6\widehat{k})\\\\\overrightarrow{v_{a'}}\cdot \overrightarrow{v_{b'}}=1\cdot 2+5\cdot 3+3\cdot 6=35$

7 0

4 years ago

Which answer describes the calculations that could be used to solve this problem? chelsea bought 6 tickets for the county fair.

timurjin [86]

B. is the correct statement.

Hope that helps you

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4 years ago

Write the equation of the quadratic given the following information:

xenn [34]

<span>y=a((x-h)^2)+k
Vertex=(h,k)
1. Vertex (5,-1) Point (2,4)
y=a((x-5)^2)+(-1)
f(2)=4
4=a((2-5)^2)+(-1)
4=a(-3)^2-1
4=a*9-1
5=a*9
5/9=a
y=(5/9)((x-5)^2)-1
2. Vertex (-2,0) Point (-1,-7)
y=a((x+2)^2)+0
y=a((x+2)^2)
f(-1)=-7
-7=a(-1+2)^2
-7=a(1)^2
a=-7
y=-7(x+2)
(x-h)^2=4(d)(y-k)
3. Vertex (0,0) Focus (0,2)
d=f-v
d=2
(x^2)=4(2)(y)
(x^2)=8y
f(0)=0
4. Focus (-3,4) Directrix y= -2
(x-h)^2=4(d)(y-k)
d=(4-(-2))/2=6/2=3
(x-h)^2=4(3)(y-k)
h=-3
k=(-2+4)/2=(2)/2=1
(x+3)^2=4(3)(y-1)
(x+3)^2=12(y-1)</span>

6 0

3 years ago

The circle with center O has a minor arc BSA with a length of

tangare [24]

Answer:

D. $\frac{27\pi}{2}$ inches.

Step-by-step explanation:

We have been given that the circle with center O has a minor arc BSA with a length of $3\pi^{2}$ inches. The central angle is 40°.

To find the circumference of circle we will use formula:

$\frac{\text{Central angle}}{2\pi}=\frac{\text{Arc length}}{2\pi r}$ , where $2\pi$ = measure of 360 degrees in radians and $2\pi r$ = circumference of circle.