Lim as x approches 0 of (e^(5x) - 1 - 5x)/x^2 = lim as x approaches 0 of (5e^(5x) - 5)/2x = lim as x approaches 0 of 25e^(5x)/2 = 25/2 = 12.5
Answer:
-2x+3 is the answer of this
V = 30cm³
H = 3cm
W = 5cm
L = ?
V = H × W × L
therefore:
3 × 5 × L = 30
15L = 30
L = 30 : 15
<u>L = 2 (cm)</u>
