Answer:
positive is the correct answer
The line y = 7 would just be a Horizontal line on 7
Basically, you go up 7 units then draw a straight horizontal line across
Hope this helps!
You move the decimal point forward until it reaches the one so it looks like this:
1.4 x 10⁵
the exponent, 5, just tells you how many spaces the decimal point moved.
For the first question, simply find a point that is on the line segment. For the second question, knowing that in quadrant iii the x values are negative and the y values are also positive using this fact find the point that has x negative and y positive.
In order to solve this, we need to select the function that meets our constraints. Since x^2 - 5 occurs when x is less than 3, and the x-value we are given is -4, we use the first function.
f(-4) = (-4)^2 - 5
f(-4) = 16 - 5
f(-4) = 11
