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Marina CMI [18]

3 years ago

6

HELP HELP HELP HELP WOPFOPOPMPOMGOPRDAGS

1 answer:

Basile [38]3 years ago

4 0

Answer:

Step-by-step explanation:

You can't ever let this go negative. At least not at the grade you are in.

It can be 0.

So the domain must start at x = 7

sqrt(5*7 - 35) = sqrt(0) = 0

x can have any value (including 7) between 7 and infinity. If you choose a number less than 7 (like 6) the square root will go negative and that's not to be done.

So the interval is

7 ≤ x < ∞

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Calculate the slope of each segment (just need a couple example problems and step by step, no need to answer all. Will mark brai

Tpy6a [65]

Answer:

12) Line segment AB

$m_{AB} = \frac{7-4}{10-4}= \frac{1}{2}$

13) Line segment CD

$m_{CD} = \frac{6-11}{15-13}=-\frac{5}{2}$

14) Line segment EF

$m_{EF} = \frac{7-11}{4-3}= -4$

15) Line segment GH

$m_{GH} = \frac{5-2}{8-6}= \frac{3}{2}$

16) Line segment IJ

$m_{IJ} = \frac{0-(-6)}{0-4}=-\frac{3}{2}$

17) Line segment KL

$m_{KL} = \frac{-2-(-3)}{5-(-2)} = \frac{1}{7}$

18) Line segment MN

$m_{MN} = \frac{5-5}{3-(-4)} = 0$

19) Line segment OP

$m_{OP} = \frac{4-(-2)}{13-13} = \frac{1}{0}$

20) Line segment QR

$m_{QR} = \frac{7-11}{-2-(-7)} = -\frac{4}{5}$

21) Line segment ST

$m_{ST} = \frac{-2-(-3)}{10-9} = 1$

Step-by-step explanation:

Coordinates are now described: $A(x,y) = (4,4)$ , $B(x,y) = (10, 7)$ , $I(x,y) = (-6, 4)$ , $J(x,y) = (0,0)$ , $Q(x,y) = (-7,11)$ , $R(x,y) = (-2,7)$ , $C(x,y) = (13,11)$ , $D(x,y) = (15, 6)$ , $K(x,y) = (-2, -3)$ , $L(x,y) = (5,-2)$ , $S(x,y) = (9,-3)$ , $T(x,y) = (10, -2)$ , $E(x,y) = (3, 11)$ , $F(x,y) = (4,7)$ , $M(x,y) = (-4,5)$ , $N(x,y) = (3, 5)$ , $G(x,y) = (6,2)$ , $H(x,y) = (8,5)$ , $O(x,y) = (13,-2)$ , $P(x,y) = (13,4)$

The slope of each line segment is calculated by applying definition of secant line:

12) Line segment AB

$m_{AB} = \frac{7-4}{10-4}= \frac{1}{2}$

13) Line segment CD

$m_{CD} = \frac{6-11}{15-13}=-\frac{5}{2}$

14) Line segment EF

$m_{EF} = \frac{7-11}{4-3}= -4$

15) Line segment GH

$m_{GH} = \frac{5-2}{8-6}= \frac{3}{2}$

16) Line segment IJ

$m_{IJ} = \frac{0-(-6)}{0-4}=-\frac{3}{2}$

17) Line segment KL

$m_{KL} = \frac{-2-(-3)}{5-(-2)} = \frac{1}{7}$

18) Line segment MN

$m_{MN} = \frac{5-5}{3-(-4)} = 0$

19) Line segment OP

$m_{OP} = \frac{4-(-2)}{13-13} = \frac{1}{0}$

20) Line segment QR

$m_{QR} = \frac{7-11}{-2-(-7)} = -\frac{4}{5}$

21) Line segment ST

$m_{ST} = \frac{-2-(-3)}{10-9} = 1$

8 0

3 years ago

-15v-40=23-8v solve equation

Ahat [919]

-15v-40=23-8v

-7v=63
v=-9

4 0

4 years ago

Read 2 more answers

Which of the following is the simplest form of this expression?

Softa [21]

Step-by-step explanation:

which expression there is no expression here

4 0

3 years ago

Anyone... Someone... please.... hElP mE. im getting sick of this online school stuff

Kobotan [32]

Answer:

30,40,50

Step-by-step explanation:

If it is a right triangle then the pythagorean theorum would work

a^2+b^2=c^2

30^2+40^2=50^2

900+1600=2500

2500=2500

this means that 30,40,50 is the right answer

*******extra********

also 30,40,50 is a pythagorean triplet

pythagorean triplets form right angles

this one came from the original triplet of 3,4,5---just multiply by 10

6 0

3 years ago

Solve the following system using any method you choose:

ahrayia [7]

Answer:

(4,2)

Step-by-step explanation:

(4)-4(2)=-4

5(4)-4(2)=12

5 0

3 years ago

Read 2 more answers