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STALIN [3.7K]
3 years ago
15

Stuffed animals each weighing 1/4

Mathematics
2 answers:
Ahat [919]3 years ago
5 0

Answer:

1 and 1/2 pounds = 1.5 pounds

1.5 pounds ÷ .25 pounds = 6 toys

Step-by-step explanation:

Natali5045456 [20]3 years ago
4 0

Answer:

6

Step-by-step explanation:

because  if its 1&1/2 then it would be 6

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marishachu [46]

Solution: The needed answer for first blank is 1 and the needed a for second blank is 1.

Explanation:

The given equation is y=x^2+2x-1.

The form of perfect square is (x+y)^2=x^2+2xy+y^2.

The given equation can be written as y=(x^2+2x)-1.

To make the perfect square we can add or subtract (\frac{b}{2a})^2 in the given equation. Where, a is coefficient of x^2 and b is coefficient of x. In the parenthesis the coefficient of x^2 is 1 and coefficient of x is 2.

(\frac{b}{2a})^2=(\frac{2}{2(1)})^2=1

So, the given equation is written as y=(x^2+2x+1)-1-1

y=(x+1)^2-2

Therefore, the needed answer for first blank is 1 and the needed a for second blank is 1.

4 0
3 years ago
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Credit sales are collected as follows:65 percent in the month of the sale.25 percent in the month after the sale.10 percent in t
Vitek1552 [10]

Answer:

Step-by-step explanation:

a) November sales = (Total Uncollected Sales - Uncollected Sales from December) / Collection rate after two months

= ($121,100 - $87,300) / 0.20

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b) December sales = Uncollected sales from December / Collection rate of the previous month sales,

Therefore: December sales = $87,300 / 0.45 = $194,000

December sales = $194,000.00

c) Each month's collection for the company are:

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January collections = 0.20($169000.00) + 0.25($194,000.00) + 0.55($132,000)

January collections = $154,900.00

February collections = 0.20($194,000.00) + 0.25($132,000) + 0.55($149,000)

February collections = $153,750.00

March collections = 0.20($132,000) + 0.25($149,000) + 0.55($164,000)

March collections = $153,850.00

4 0
4 years ago
The cell phone company will add −$2.74 to your next bill foreach of the 4 months you were overcharged.Will your next bill increa
velikii [3]

Answer:

It will be

Step-by-step explanation:

5 0
3 years ago
A single-server waiting line system has an arrival pattern characterized by a Poisson distribution with 3 customers per hour. Th
sweet-ann [11.9K]

Answer:

18 minutes

Step-by-step explanation:

Given that:

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To hour, we have:

s = \dfrac{60}{12}

s = 5 customers/ hour

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To minutes;

= 3 \times \dfrac{60}{10} \ minutes

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3 0
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Answer:

b

Step-by-step explanation:

7 0
3 years ago
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