No, when you have a zero in that space you don't necessarily need an addendum unless it helps you.
-1.5 is the answer because it is 75
(-5/8)(X) = -0.4
(-5/8)(X) = -4/10
X = (-4/10) / (-5/8)
X = (4/10) / (5/8)
X = (4/10)(8/5)
X = (2/5)(8/5)
X = 16/25
Letter D
Speed of the ship in the second hour = (62.5 * x ) / 100 kph.
In third hour it is [(62 * x) / 100 ] * x/100]
is 4th hour its is the above * x/100 again so we can now form the equation
62.5x x x
------- * ---- * ---- = 32
100 100 100
62,5 x^3 = 32,000,000
x^3 = 512,000
x = 80 <----- Answer to (a)
(b) Ship travels 62.5 in first hour then this falls by a common ratio of 0.8 each hour so we have a geometric sequence
Dist travelled in 6 hours = a1 1 - r^n
-------- = 62.5* (1 - 0.8^6) / 1 -0.8 = 230.56
1 - r
Answer is 230.56 km
![r=\sqrt[3]{\frac{3V}{4\pi}}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%7D%7D)
![r=\sqrt[3]{\frac{3(36\pi)}{4\pi}}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3%2836%5Cpi%29%7D%7B4%5Cpi%7D%7D)
![r=\sqrt[3]{27}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B27%7D)
