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Virty [35]
3 years ago
6

Find the measure of the angle, round to the nearest tenth: Sin X = .7547

Mathematics
1 answer:
dimulka [17.4K]3 years ago
4 0
SIN(x) = .7547
X = INVERSE-SIN(.7547)
X = 49.0 degrees
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There are 96 football players at all levels at Davenport High School. If two-thirds of the players make the honor roll for their
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64 players
Reason- 2/3 of 96 = (32 x 2 = 64) telling us how many got on the list
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1 year ago
Start at 200. create a pattern that multiplies each number by 2. stop when you have 5 numbers
s2008m [1.1K]

Answer:

200 → 400 → 800 → 1600 → 3200

Step-by-step explanation:

starting at 200 and multiplying by 2 until you have 5 numbers.

8 0
2 years ago
Solve 5/8+3/4 -2/3-5/6
alexira [117]

Answer:

-.125

Step-by-step explanation:

5/8 + 3/4 solve

2/3 - 5/6 solve

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3 0
3 years ago
Read 2 more answers
Math be like 0-0????
pashok25 [27]

Answer:  A & C

<u>Step-by-step explanation:</u>

HL is Hypotenuse-Leg

A) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH

   a leg from ΔABC ≡ a leg from ΔFGH

   Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH

B) a leg from ΔABC ≡ a leg from ΔFGH

   the other leg from ΔABC ≡ the other leg from ΔFGH

   Therefore LL (not HL) Congruency Theorem can be used.

C) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH

   at least one leg from ΔABC ≡ at least one leg from ΔFGH

   Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH

D) an angle from ΔABC ≡ an angle from ΔFGH

   the other angle from ΔABC ≡ the other angle from ΔFGH

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5 0
3 years ago
2. The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability th
coldgirl [10]

Answer:

0.30

Step-by-step explanation:

Probability of stopping at first signal = 0.36 ;

P(stop 1) = P(x) = 0.36

Probability of stopping at second signal = 0.54;

P(stop 2) = P(y) = 0.54

Probability of stopping at atleast one of the two signals:

P(x U y) = 0.6

Stopping at both signals :

P(xny) = p(x) + p(y) - p(xUy)

P(xny) = 0.36 + 0.54 - 0.6

P(xny) = 0.3

Stopping at x but not y

P(x n y') = P(x) - P(xny) = 0.36 - 0.3 = 0.06

Stopping at y but not x

P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24

Probability of stopping at exactly 1 signal :

P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30

8 0
3 years ago
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