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I am Lyosha [343]
3 years ago
12

Please help me with this question. I am very confused.

Mathematics
1 answer:
Oksanka [162]3 years ago
7 0
I think u do the ones in the parenthesis first bc of PEMDAS since it's both negative it become positive and u can cross out both the 2's and that leaves u with 1/7 and then u just times 1/7 with 8 and then u get 8/7

hoped this helped! :)
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What’s the correct answer
forsale [732]
1/6.

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So, 2 is one of the six sides of the dice: 1/6
8 0
3 years ago
Find the derivative of <br><img src="https://tex.z-dn.net/?f=%20y%20%3D%20%5Csqrt%5B3%5D%7Bx%7D%20" id="TexFormula1" title=" y =
MAXImum [283]

Answer:

\displaystyle y'(27) = \frac{1}{27}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Exponential Rule [Root Rewrite]: \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}
  • Exponential Rule [Rewrite]: \displaystyle b^{-m} = \frac{1}{b^m}

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

<u>Step 1: Define</u>

y = ∛x

x = 27

<u>Step 2: Differentiate</u>

  1. [Function] Rewrite [Exponential Rule - Root Rewrite]:                               \displaystyle y = x^{\frac{1}{3}}
  2. Basic Power Rule:                                                                                         \displaystyle y' = \frac{1}{3}x^{\frac{1}{3} - 1}
  3. Simplify:                                                                                                         \displaystyle y' = \frac{1}{3}x^{-\frac{2}{3}}
  4. Rewrite [Exponential Rule - Rewrite]:                                                           \displaystyle y' = \frac{1}{3x^{\frac{2}{3}}}

<u>Step 3: Solve</u>

  1. Substitute<em> </em>in <em>x</em> [Derivative]:                                                                           \displaystyle y'(27) = \frac{1}{3(27)^{\frac{2}{3}}}
  2. Evaluate exponents:                                                                                     \displaystyle y'(27) = \frac{1}{3(9)}
  3. Multiply:                                                                                                         \displaystyle y'(27) = \frac{1}{27}

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

8 0
3 years ago
Una bañera en forma de trapecio tiene un area de 60 metro ademas se sabe que su base mayor es 3/2 mas grande que su base menor c
valkas [14]

Respuesta:

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Explicación paso a paso:

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Área, A = 60

Sea una base más pequeña = a = 18;

b = 18 + 3/2 = 19,5

La altura se puede calcular así;

60 = 1/2 (18 + 19,5) h

60 * 2 = 37,5 horas

120 = 37,5 h

h = 120 / 37,5

h = 3,2 metros

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ANTONII [103]

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Lana71 [14]
GED is 43 
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