Given set S = <span>{A, B, C, D, E, F, G, H}
There are 8 elements in set S and we are to choose 3 letters at random, the number of ways to choose such is x. It is simply similar to choosing 5 letters at random, which is also equal to x. Since order doesn't matter, n! / (n-m)! where n = 8 and m = 3, which is 336 ways. </span>
        
             
        
        
        
Answer:

See explanation below.
Step-by-step explanation:
For this case we define first some notation:
A= A new training program will increase customer satisfaction ratings 
B= The training program can be kept within the original budget allocation
And for these two events we have defined the following probabilities

We are assuming that the two events are independent so then we have the following propert:

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

And using the De Morgan laws we know that:

So then we can write the probability like this:

And using the complement rule we can do this:

Since A and B are independent we have:

And then our final answer would be:

 
        
             
        
        
        
Answer:
a=  2/5
b= 30
c= 18
d=   3:2
e=  No, because the fraction or ratio is the same, all you need to do is simplify it!
 
        
             
        
        
        
Tan(12)=-0.6358599287. That means -0.6358599287 = 10/x so you can swap the x to the other side to make x = 10/-0.6358599287 Which equals -15.7 rounded to the nearest tenth.