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DaniilM [7]
3 years ago
9

Do you guys know how to solve this? Help me out please #9 and 10

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
8 0

Answer:

Q9

X = 3

OG 22

GW 11

OW 11

Q10

X = 13/2

CF 18

CK 36

KF 18

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Question 27 (1 point)
Arada [10]

Answer: y=2x+1

Step-by-step explanation:

plug in the points in to the equation to see what you get

7 0
3 years ago
Mario has $150 to spend on food for a party. He ordered pizzas that cost $8 each and bottles of soda that cost $2 each which ine
White raven [17]

Answer:

8p + 2s <= 150

Step-by-step explanation:

Let p = number of a pizza.

Let s = price of a bottle of soda.

The inequality is

8p + 2s <= 150

7 0
3 years ago
*****50 POINTSSSS*****
defon

Answer:

<h3>Given</h3>
  • m∠REG = 78°
  • mAR = 46°
  • ER ≅ GA
<h3>Solution</h3>
  • m∠GAR = 180° - m∠REG = 180° - 78° = 102° (supplementary angles sum to 180°)
  • m∠TAR = 1/2mAR = 1/2(46°) = 23°   (tangent chord angle is half the size of intercepted arc)
  • m∠GAN = 180° - (m∠TAR + m∠GAR) = 180° - (23° + 102°) = 55° (straight angle is 180°)
  • mAG = 2m∠GAN = 2(55°) = 110°
  • mRE = mAG = 110° (as ER ≅ GA)
  • mGE = 360° - (mAG + mAR + mRE) = 360° - (110° + 46° + 110°) = 94° (full circle is 360°)
6 0
2 years ago
At the city museum, child admission is $5.80 and adult admission is $9.60. On Friday, three times as many adult tickets as child
noname [10]
Its 74 and if its wrong im sorry but hi
7 0
3 years ago
How many different 5-person subcommittees can be formed from a club having 12 members
Wittaler [7]
Given that there are 12 persons, the first choice may be in 12 different ways, the second choice may be in 11 different ways, ther third in 10 different ways, the fourth in 9 different ways and the fith in 8 different ways, for a total of:

12x11x10x9x8 different combinations.

Now you have to take in account that 5x4x3x2 are repetitions. So you have to divide the previos counting by 5x4x3x2.

(12x11x10x9x8)/(5x4x3x2) = 792 different subcommittees.

Also, you can use the formula for combinations: C(m,n) = m! / (n! (m-n)!)

C (12, 5) = 12! / (5!) (12-5)! = [12x11x10x9x8x7!] / [5! 7!] = [12x11x10x9x8]/[5x4x3x2] = 792
3 0
2 years ago
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