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RoseWind [281]
3 years ago
13

I'LL GIVE BRAINLIEST PLS HELP

Mathematics
1 answer:
viktelen [127]3 years ago
4 0

Answer:

ok But i cant see dat stuff

Step-by-step explanation:

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Estimate this product. 89.65 x 4.75 A 4,500 B 450 C 45 D 4.5 plz hurry
Alona [7]
<u>The correct answer</u> is B.

Explanation:
89.65 is nearly 90.
4.75 is nearly 5.

To estimate the product, we will multiply 90*5, which equals 450.

7 0
3 years ago
Read 2 more answers
2. From the definition of the derivative (definition 5.3), find the derivative for each of the following functions: (a) f(x) = 6
castortr0y [4]

Answer:

a) f'(x)=6

b) f'(x)=12

c) f'(x)=2kx

Step-by-step explanation:

To find :  From the definition of the derivative find the derivative for each of the following functions ?

Solution :

Definition of the derivative is

f'(x)= \lim_{h \to 0}(\frac{f(x+h)-f(x)}{h})

Applying in the functions,

a) f(x)=6x

f'(x)= \lim_{h \to 0}(\frac{6(x+h)-6x}{h})

f'(x)= \lim_{h \to 0}(\frac{6x+6h-6x}{h})

f'(x)= \lim_{h \to 0}(\frac{6h}{h})

f'(x)=6

b) f(x)=12x-2

f'(x)= \lim_{h \to 0}(\frac{12(x+h)-2-(12x-2)}{h})

f'(x)= \lim_{h \to 0}(\frac{12x+12h-2-12x+2}{h})

f'(x)= \lim_{h \to 0}(\frac{12h}{h})

f'(x)=12

c) f(x)=kx^2 for k a constant

f'(x)= \lim_{h \to 0}(\frac{k(x+h)^2-kx^2}{h})

f'(x)= \lim_{h \to 0}(\frac{k(x^2+h^2+2xh-kx^2)}{h})

f'(x)= \lim_{h \to 0}(\frac{kx^2+kh^2+2kxh-kx^2}{h})

f'(x)= \lim_{h \to 0}(\frac{h(kh+2kx)}{h})

f'(x)= \lim_{h \to 0}(kh+2kx)

f'(x)=2kx

6 0
3 years ago
Determine if the set of vectors shown to the right is a basis for IR3 If the set of vectors is not a basis, determine whether it
r-ruslan [8.4K]

Answer:

The problem is clearly solved in the attachment

4 0
3 years ago
Which of these is a point-slope equation of the line that is perpendicular to
stellarik [79]

Answer:

D

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y - 3 = 4(x - 10) ← is in point- slope form

with slope m = 4

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{4}

The perpendicular line passes through (- 3, 7), hence

y - 7 = - \frac{1}{4}(x - (- 3)), that is

y - 7 = - \frac{1}{4}(x + 3) → D

5 0
3 years ago
"Seven less than a number, divided by 5, is -2." Can you turn it into a equation please??
Xelga [282]

Answer:

Seven less than a number, divided by 5, is -2." Can you turn it into a equation please??

let the number be x

x-7/5= -2

x-7= -10

x= -10+7

x= -3

Step-by-step explanation:

7 0
4 years ago
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