Answer:
Step-by-step explanation:
The ans is choice D. since there nothing under 5x, imagine there is a 1 under. After that, you can simply cross multiply, so it would be 1(6+8x)= 2(5x). 6+8x= 10x now combine like terms so subtract 8x from both sides and divide 6 by 2 and you will get 3
The quadratic equation use to determine the thickness of the frame, x is 4x² + 10x - 1 = 0.
The correct option is D.
<h3>What is a quadratic equation ?</h3>
A quadratic equation is an algebraic equation of the second degree in x.. The quadratic equation is written as ax2 + bx + c = 0, where x is the variable, a and b are the coefficients, and c is the constant term.
<h3>
According to the given information:</h3>
Total area = 7 square feet
and,
Total area = Length x Width
So,
7 = (2x + 3)(2x + 2)
7 = 4x2 + 4x + 6x + 6
7 = 4x2 + 10x + 6
4x2 + 10x + 6 - 7 = 0
4x2 + 10x - 1 = 0
Hence,
The quadratic equation use to determine the thickness of the frame, x is 4x² + 10x - 1 = 0.
To know more about quadratic equation visit:
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I understand that the question you are looking for is:
Mary wants to hang a mirror in her room. the mirror and frame must have an area of 7 square feet. The mirror is 2 feet wide and 3 feet long. Square with an inner frame with height of 2 ft on the left frame and width of 3 ft on the top. Arrow on the bottom frame with an x and an arrow on the right frame with an x. Which quadratic equation can be used to determine the thickness of the frame, x?
A. x² + 14x - 2 = 0
B. 2x² + 10x - 7 = 0
C. 3x² + 12x - 7 = 0
D. 4x² + 10x - 1 = 0
The answer is: c
Explination 30-9=21
Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
