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Free_Kalibri [48]
3 years ago
8

Find the volume of this cube in cm³​

Mathematics
1 answer:
Degger [83]3 years ago
8 0

Answer:

<u>It</u><u> </u><u>is</u><u> </u><u>c</u><u>:</u><u> </u><u>1</u><u>5</u><u>.</u><u>6</u><u>2</u><u>5</u><u> </u><u>cm³</u>

Step-by-step explanation:

Formular for cube volumes:

{ \tt{volume = (side \times side \times side)}} \\ { \tt{v = (s_{1} \times s_{2} \times s_{3}) }}

since sides of a cube are identical:

{ \sf{s_{1} = {s_{2} =  {s_{3}}}}}

Therefore:

{ \sf{volume = (250 \times 250 \times 250) \: mm {}^{3} }} \\  { \sf{v =15,625,000 \:  {mm}^{3}  }}

but 1 mm³ = 0.000001 cm³

{ \sf{v = (15,625,000 \times  \{1 \times  {10}^{ - 6} \} ) \: cm}} \\ { \sf{v = 15.625 \:  {cm}^{3} }}

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Square lMNO is shown in the diagram below what are the coordinates of the midpoint of a diagonal LN
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Answer:

The coordinates of the midpoint of LN are (-2\frac{1}{2},4\frac{1}{2})

answer (4)

Step-by-step explanation:

* Lets explain how to find the midpoint of a line

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- Let the coordinates of point L are (x1 , y1) , the coordinates of point

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∴ x1 = -6 , x2 = 1 and y1 = 1 , y2 = 8

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∵ x=\frac{-6+1}{2}=\frac{-5}{2}=-2\frac{1}{2}

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∴ The coordinates of the midpoint are (-2\frac{1}{2},4\frac{1}{2})

* The coordinates of the midpoint of LN are (-2\frac{1}{2},4\frac{1}{2})

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