The answers are A, C and D
Answer:
Linearly Dependent for not all scalars are null.
Step-by-step explanation:
Hi there!
1)When we have vectors like
we call them linearly dependent if we have scalars
as scalar coefficients of those vectors, and not all are null and their sum is equal to zero.
When all scalar coefficients are equal to zero, we can call them linearly independent
2) Now let's examine the Matrix given:

So each column of this Matrix is a vector. So we can write them as:
Or
Now let's rewrite it as a system of equations:

2.1) Since we want to try whether they are linearly independent, or dependent we'll rewrite as a Linear system so that we can find their scalar coefficients, whether all or not all are null.
Using the Gaussian Elimination Method, augmenting the matrix, then proceeding the calculations, we can see that not all scalars are equal to zero. Then it is Linearly Dependent.



Answer:
here
Step-by-step explanation:
from left to right
81, 27, 9, 3, 1
Hi! So to solve for these, all you have to do is keep PEDMAS in mind. For example, for 2x^3 (Just a fancy way of writing "to the third power") first plug in 3: 2(3)^3 and take it to the third power because E (exponent) comes before M (multiplication) in PEDMAS. You should get 2(27) which then equals 54. Hope this helps:)