Answer:
7,897.30 miles
Step-by-step explanation:
It is given that the North Pole is at a distance of 3,949 miles from the center of the earth.
We also know that the sea floor is below 2.4 miles from the sea level.
It is given that a submarine is located at the sea floor near North Pole. Hence, the distance of the submarine from the center of the earth would be
3949 - 2.4 = 3946.6 miles.
On the other hand, the South Pole is given to be at an elevation of 1.7 miles from the sea level.
Since we know that the sea level is at a distance of 3949 miles from the center of the earth, we can immediately calculate the distance of the South Pole from the center of the earth to be
3949 + 1.7 = 3950.7 miles.
Putting all of this together, we see that the center of the earth is at a distance of 3946.6 miles from the submarine near the North Pole, and the center of the earth in turn is 3950.7 miles from the South Pole.
Hence, the distance between the submarine and a person on the South Pole = 3946.6 + 3950.7 = 7897.3 miles.
Answer:
B and C
Step-by-step explanation:
All you need to do is find the answer for all of them and see which ones match
Original:
6 + (-4) - 5
6 - 4 - 5
2 - 5
<u><em>-3</em></u>
This is the answer for the original expression, now we need to see which one is the correct match....
A. -(-6 + 4 ) - 5
2 negatives being subtracted gives you a positive
6 + 4 - 5
10 - 5
5
Incorrect, so now we know its not A
B. 6 - 4 - ( -5)
Again 2 negatives give you a positive
6 - 4 + (5)
6 - 9
-3
Correct, so now we know its B
C. 6 - (4 + 5)
PEMDAS so do the parenthesis first
6 - 9
-3
Correct, so now we it's C.
D. 6 + 4 - 56
10 - 56
-46
Incorrect, so now we know its not D
E. -(-6) + (-4) - (-5)
Again, 2 negatives equal a positive
6 - 4 + 5
2 + 5
7
Incorrect so now we know its not E
The correct answer is C
Hope this helped!
Have a supercalifragilisticexpialidocious day!
1. Domain.
We have
in the denominator, so:
![x^2-2x-3\neq0\\\\(x^2-2x+1)-4\neq0\\\\(x-1)^2-4\neq0\\\\(x-1)^2-2^2\neq0\qquad\qquad[\text{use }a^2-b^2=(a-b)(a+b)]\\\\(x-1-2)(x-1+2)\neq0\\\\ (x-3)(x+1)\neq0\\\\\boxed{x\neq3\qquad\wedge\qquad x\neq-1}](https://tex.z-dn.net/?f=x%5E2-2x-3%5Cneq0%5C%5C%5C%5C%28x%5E2-2x%2B1%29-4%5Cneq0%5C%5C%5C%5C%28x-1%29%5E2-4%5Cneq0%5C%5C%5C%5C%28x-1%29%5E2-2%5E2%5Cneq0%5Cqquad%5Cqquad%5B%5Ctext%7Buse%20%7Da%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D%5C%5C%5C%5C%28x-1-2%29%28x-1%2B2%29%5Cneq0%5C%5C%5C%5C%0A%28x-3%29%28x%2B1%29%5Cneq0%5C%5C%5C%5C%5Cboxed%7Bx%5Cneq3%5Cqquad%5Cwedge%5Cqquad%20x%5Cneq-1%7D)
So there is a hole or an asymptote at x = 3 and x = -1 and we know, that answer B) is wrong.
2. Asymptotes:
We have only one asymptote at x = -1 (and hole at x = 3), thus the correct answer is A)
The answer would be $5 bills
5*4 = 20 and he spent 5 you would only have 3 $5 bills.
Answer:
arithmetic progression problem
