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3 years ago

PLZZ HELP ME I'M TIMED

Mathematics

1 answer:

MrRa [10]3 years ago

6 0

Answer:

Step-by-step explanation:

The answer is d

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A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 436.0 gram setting. It

Vilka [71]

Answer:

We conclude that the machine is under filling the bags.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 436.0 gram

Sample mean, $\bar{x}$ = 429.0 grams

Sample size, n = 40

Alpha, α = 0.05

Population standard deviation, σ = 23.0 grams

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 436.0\text{ grams}\\H_A: \mu < 436.0\text{ grams}$

We use one-tailed(left) z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{429 - 436}{\frac{23}{\sqrt{40}} } = -1.92$

Now, $z_{critical} \text{ at 0.05 level of significance } = -1.64$

Since,

$z_{stat} < z_{critical}$

We reject the null hypothesis and accept the alternate hypothesis. Thus, we conclude that the machine is under filling the bags.

8 0

3 years ago

The double-bar graph shows the win-loss records for the Carolina Panthers football team in the years 1995-2001. A bar graph titl

lina2011 [118]

Answer:

the answer is A

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Expressed as a product of its prime factors in index form, a number N is

Elena-2011 [213]

ANSWER

$5N^2=3^{2} \times 5^{5} \times x^{6}$

EXPLANATION

$N=3\times5^2 \times x^3$ .

$5N^2=5(3\times5^2 \times x^3)^2$

Recall this property of exponents;

$(a^m)^2=a^{m} \times a^m$

So our product becomes;

$5N^2=5(3\times5^2 \times x^3) \times (3\times5^2 \times x^3)$

$5N^2=5\times 3\times 3 \times 5^2 \times 5^2 \times x^3 \times x^3$

$5N^2=3\times 3\times 5 \times 5^2 \times 5^2 \times x^3 \times x^3$

Recall this law of exponents:

$a^m \times a^n =a ^{m+n}$

$5N^2=3^{1+1} \times 5^{1+2+2} \times x^{3+3}$

$5N^2=3^{2} \times 5^{5} \times x^{6}$

7 0

3 years ago

In Exercise, find the derivative of the function. y = 32e0.23t

TEA [102]

Answer:

$y'=7.36e^{0.23t}$

Step-by-step explanation:

$y=32e^{0.23t}$

take derivative with respect to t

$\frac{dy}{dt} =32\frac{d(e^{0.23t})}{dt}$

derivative of e^t is e^t

derivative of 0.23t is 0.23

$\frac{dy}{dt} =32 \frac{d(e^{0.23t})}{dt}$

Apply chain rule

$\frac{dy}{dt} =32(e^{0.23t})(0.23)$

$y'=7.36e^{0.23t}$

3 0

3 years ago

Can y'all solve and show me the steps on how you got it

Tju [1.3M]

The x-coordinate of the right-most point of S' is 4. In the original, it is 6. The dilation multiplier is 4/6 = 2/3.

Selection B matches that.

5 0

3 years ago