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vova2212 [387]
3 years ago
11

How can i solve that equation

Mathematics
1 answer:
forsale [732]3 years ago
8 0

Answer:

C and E

Step-by-step explanation:

3 \tan( \beta )  = 2.  \:  \:  \:  \:  \tan( \beta )  =  \frac{2}{3}

\frac{h}{x}  =  \tan( \beta )  =  \frac{2}{3}

if \:  \: h = 2 \:  \:  \: x = 3 \:  \:  \: and \:  \:  \: t =  \sqrt{ {h}^{2} + x }

C. t =  \sqrt{13} ✅

○♧○♧○♧○♧○♧○♧○♧○♧○♧○♧○♧○

if \: \: \: h = 4 \:  \:  \:  \: x = 6 \:  \:  \: and \:  \:  \: t =  \sqrt{ {h}^{2}  +  {x}^{2} }

E. t = 2 \sqrt{13} ✅

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The answer to your question is x = 64; y = 20

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