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Viktor [21]
3 years ago
9

Mrs. Gordon had $40 to spend on cookies and pies. She bought 4 cookies, each of which cost $3. She spent twice as much on pies a

s she spent on cookies. Mrs. Gordon bought 3 pies that each cost the same amount. How much did each pie cost? $ How much money did Mrs. Gordon have left after buying the cookies and pies? $
Mathematics
1 answer:
DiKsa [7]3 years ago
4 0
First, multiply $3 by 4 to get $12 spent on cookies.  Then, you multiply $12 by 2 to know that the pies cost $24.  You then divide the $24 by 3 to get $6 per pie.  Meaning, each pie had cost $6.  You add the $12 and $24 together to get $36.  Finally, you subtract $36 from $40 to know that she only has $4 left.
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A 7000.00 principal is invested in 2 accounts, 1 earning 3%interest the other 7% interest with the total interest for the year 2
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Answer:

The amount in the first account is $5,700

The amount in the second account is $1,300

Step-by-step explanation:

Let the mount invested in the first account be x and the one invested in the second account be y.

Then the total principal is x+y=7000---->(1)

The interest in the first account is .03*x

The interest in the first account is .07*y

The total interest for the year  is 262.00.

This implies that:

0.03x+0.07y=262---->(2)

We solve the two equations simultaneously to get:

x=5,700 and y=1,300

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3 years ago
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<span>I think you meant this: (3m/m-6)*(5m^3-30m^2/5m^2)
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