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Mekhanik [1.2K]
3 years ago
7

Solve the following problem. Round to one decimal place if necssary.

Mathematics
1 answer:
son4ous [18]3 years ago
3 0

Answer:

x = 16.1051577

Step-by-step explanation:

tan0 = opp/adj

tan0 = 14/x

tan(49)× 14 = 16.1051577

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All you need to do is move the point one place to the right both sides

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3 years ago
Find the area of a circle with a Radius = 4 ft. Use 3.14 for and round to 2 decimal places.
bagirrra123 [75]

Answer:

50.24 ft^2

Step-by-step explanation:

Well formula for area of a circle is pi(radius)^2

so the radius is 4 so you square that it’ll be 16

then do 16(3.14)

you’ll get 50.24

6 0
3 years ago
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Name the number property illustrated by this equation: 4.78+(2.5+12.66)=4.78+(12.66+2.5) PLEAESE SHOW YOUR WORK OR EXPLAIN
SSSSS [86.1K]
This is the commutative property of addition

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4 0
4 years ago
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1,8,27; 64; Rule Missing numbers​
zubka84 [21]

Answer:

  rule: f(n) = n³

  missing numbers: 125, 216, 343, 512, 729

Step-by-step explanation:

Your familiarity with the cubes of small integers helps you recognize each of these numbers is a cube. Their sequence is the sequence of cubes of increasing natural numbers.

  1 = 1·1·1 = 1³

  8 = 2·2·2 = 2³

  27 = 3·3·3 = 3³

  64 = 4·4·4 = 4³

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The rule is ...

  f(n) = n³

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7 0
2 years ago
Adrian's backyard pool contains 6.4 gallons of water. Adrian will begin filling his pool at a rate of 4.1 gallons per second. Da
nirvana33 [79]

Answer:

The data that we have is:

"Adrian's backyard pool contains 6.4 gallons of water. Adrian will begin filling his pool at a rate of 4.1 gallons per second."

Then we can write the amount of water in Adrian's pool as a linear function:

A(t) = 6.4gal + (4.1gal/s)*t

Where t is our variable and represents time in seconds.

We also know that:

"Dale's backyard pool contains 66.4 gallons of water. Dale will begin draining his pool at a rate of 0.9 gallons per second. "

We can also model this with a linear function:

D(t) = 66.4 gal + (0.9gal/s)*t

Both pools will have the same amount of water when:

D(t) = A(t)

So we can find the value of t:

6.4gal + (4.1gal/s)*t = 66.4 gal + (0.9gal/s)*t

(4.1gal/s)*t - (0.9gal/s)*t = 66.4gal - 6.4gal

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In 18.75 seconds both pools will have the same amount of water.

4 0
4 years ago
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