What are the domain and range of the function f(x)=3/4x+5?

aniked [119]

FIRST QUESTION
Given points are:
A(2, -4) and B(6, 2)
Now, Use the distance formula.
distance formula = $\sqrt{ (x_{2}- x_{1})^{2} + ( y_{2} - y_{1} )^{2} }$

Now, plug the values into the formula, So,
distance = $\sqrt{ (6- 2)^{2} + ( 2 - (-4))^{2} }$

= $\sqrt{ (6- 2)^{2} + ( 2 +4))^{2} }$

= $\sqrt{ (4)^{2} + ( 6))^{2} }$

= $\sqrt{ 16+36}$

= $\sqrt{52}$

= $2 \sqrt{13}$

So, the length of AB is $2 \sqrt{13}$ .

THIRD QUESTION
Two points given are:
A(3, -2) and B(1, 1)
Also given that B is the midpoint of AC.

Let, the co-ordinates of C be C(a, b).
Now, using midpoint formula,
Midpoint = $(\frac{ x_{1}+ x_{2} }{2} , \frac{ y_{1}+ y_{2} }{2} )$

$(1, 1)=(\frac{ 3+ a }{2} , \frac{ -2+b }{2} )$

Now, equaling the ordered pair, we have,

$1=\frac{ 3+ a }{2}$ .............equation (1)

$1=\frac{ -2+b }{2}$ ................equation (2)

Now, taking equation (1)
$1=\frac{ 3+ a }{2}$

$1*2=3+a$

$2-3=a$

$a=-1$

Now, taking equation (2)
$1=\frac{ -2+b }{2}$

$1*2=-2+b$

$2+2=b$

$b=4$

So, the co ordinates of C are (a, b) which is (-1 , 4)


SECOND QUESTION:
Given equations are:
2x + 3y = 14.....................equation (1)
-4x + 2y = 4 .....................equation (2)
Taking equation (2)
-4x + 2y = 4
2y = 4 + 4x
y = (4 + 4x) / 2
y = 2 + 2x .......................equation (3)
Now, Taking equation (1)
2x + 3y = 14
Substituting the value of y from equation (3), we get,
2x + 3(2 + 2x) = 14
2x + 6 + 6x = 14
8x = 14 - 6
x = (14 - 6) / 8
x = 1

Taking equation (3)
y = 2 + 2x
Now, substituting the value of x in equation (3), we get,
y= 2 + 2 (1)
y = 2 + 2
y = 4

So, x=1 and y=4

6 0

3 years ago

What is the product? One-eighth times three-elevenths 3 over 88 1 over 22 4 over 19 35 over 88

kipiarov [429]

Answer:

$\frac{3}{88}$

Step-by-step explanation:

Given

One-eighth times three-elevenths

Required

Solve

One-eighth means 1/8

Three-elevenths means 3/11

So, mathematically; the above expression is represented as thus:

$\frac{1}{8} * \frac{3}{11}$

To solve this, we simply multiply the numerator and the denominator together.

After multiplying these together, the next is to check if the resulting can be simplified

If yes,we simplify it and if otherwise, we live it like that.

So,

$\frac{1}{8} * \frac{3}{11}$

$=\frac{1 * 3}{8 * 11}$

$= \frac{3}{88}$

At this point, the fraction can't be simplified any further.

Hence,

$\frac{1}{8} * \frac{3}{11} = \frac{3}{88}$

3 0

3 years ago

Warren drives half the distance Kendall drives to work. Kendall drives 26 more miles to work than Joe. Warren drives 15 miles. W

dem82 [27]

Answer:

15 times 2 - 26 = x

Step-by-step explanation:

Warren drives half the distance Kendall drives to work. Kendall drives 26 more miles to work than Joe. Warren drives 15 miles. Write an equation that models this situation. Use x to represent the number of miles Joe drives to work.

W X 1/2 = K

K - 26 = J

so 15 times 2 - 26 = x

6 0

3 years ago

Read 2 more answers

The linear inequality y<-2/3x+2 is graphed. Determine a solution for the inequality. A) (0,2) B) (3,0) C) (0,0) D) (0,3)

jenyasd209 [6]

Hello!

The graph y < -2/3x + 2 has a dotted line. That means that any points on the dotted line or not shaded, is not a solution to this inequality. Since we are given 4 choices, we can substitute those values into the given inequality to see if it is true.

A) (0, 2)

2 < -2/3(0) + 2

2 < 2, this is false.

B) (3, 0)

0 < -2/3(3) + 2

0 < -2 + 2

0 < 0, this is false.

C) (0, 0)

0 < -2/3(0) + 2

0 < 2, this is true.

D). (0, 3)

3 < -2/3(0) + 2

3 < 2, this is false.

To check if choice C) (0, 0) is true, we should look at the given graph.

Since (0, 0) is in the shaded area, and is not graphed on the dotted line, therefore, a solution to this linear inequality is C, (0, 0).

5 0

3 years ago

jane passes a signpost saying paris 8km how many miles is she from paris when she passes the signpost

-Dominant- [34]

Answer:

Step-by-step explanation:

3 0

3 years ago