PLS HELP ASAP WILL GIVE BRAINLIEST!!!

If Good C increases in price by 30% a pound, and this causes the quantity demanded for Good D to increase by 40%, what is the cr

dalvyx [7]

Answer:

1.3

Explanation:

Given:

If Good C increases in price by 30% a pound.

This causes the quantity demanded for Good D to increase by 40%.

Question asked:

What is the cross-price elasticity of the two goods ?

Solution:

We can find the cross-price elasticity of the two goods by this formula:

$E_{c} = \frac{ Percent\ change\ in \a \ quantity \ of \ good \ D}{Percent \ change\ in\ the\ price\ of \ good\ C}$

$E_{c} = \frac{40}{30}= 1.3$

When Good C increases in price by 30% which causes the quantity demanded for Good D to increase by 40%, then the cross-price elasticity of the is Good C and Good D is 1.3.

4 0

3 years ago

A nation has a population of 260 million people. Of these, 60 million are retired, in the military, in institutions, or under 16

aleksley [76]

Answer: 6%

Explanation:

Total population= 260 million.

Dependent population= 60 million

Employed population= 188 million

Unemployed population= 12 million

Total Labour Force= employed population + unemployed population

= 188 million + 12 million

= 200 million

Therefore total labor force= 200 million

Unemployment rate= unemployed people/ Total Labour Force×100

= 12 million/200 million×100

=0.06× 100

=6%

Unemployment rate= 6%

6 0

3 years ago

Pressure with Two Liquids, Hg and Water. An open test tube at 293 K is filled at the bottom with 12.1 cm of Hg, and 5.6 cm of wa

Radda [10]

Answer:

$1170839.28 dyn/cm^2$

16.9816 psia

$117.083928 kN/m^2$

Explanation:

To calculate the absolute pressure in the bottom of tube we need to sum the atmosferic and gauge pressure.

$P_{abs}=P_{atm}+P_G$

And the gauge pressure is given by the contributions of columns of water ( $P_{w}$ ) and mercury( $P_{Hg}$ ), we can calculate the contribution of each column as:

$P= \rho g h$ (*)

where $\rho$ is the respective density, g gravity and h is height.

So we have all the data required to use the above equations ( $P_{atm}$ , height and density of each column) we only need to be carefully with the units.

For simplicity we can to express all pressure contributions in mmHg ( $P_{atm}$ , $P_{w}$ and $P_{Hg}$ ). Note that the units "x" mmHg means the pressure at the bottom of a column of mercury of "x" mm high. For example, in this case we have a column 12.1 cm of Hg, that is a column of 121 mmHg (passing from cm to mm only requires multiply by 10) pressure exerted by that column is 121 mmHg.

Now pressure of 5.6 cm (56 mm) of water would be 56 mm of water, but it is not the same that mmHg, since the density of water is lower, the pressure exerted by 1 mm of water is lower than the exerted by 1 mm of Hg. The conversion between mmHg and mm of water is given by the relation between the densities.

$mmHg=\frac{\rho_w*mmH_2O}{\rho_{Hg}}$

$mmHg=\frac{0.998*mmH_2O}{13.55}=0.0737 mmH_2O$

And pressure of water in mmHg is

$0.0737*56=4.1246 mmHg$

The absolute pressure is:

$P_{abs}=P_{atm}+P_G= 756 + 121 + 4.1246 = 881.1246 mmHg = 88.11246cmHg$

To pass to dyn/cm^2 units we need to use the equation (*)

$P= \rho g h = 13.55 \frac{g}{cm^3} * 980.665 \frac{cm}{s^2} * 88.11246 cmHg = 1170839.28 \frac{g}{cm s^2} = 1170839.28 \frac{dyn}{cm^2}$

Note: We need to use cm Hg for units coherence

Now passing from dyn/ $cm^2$ to kN/ $m^2$ (or kPa) we need to consider that 1 dyn is $10^{-8}$ kN and 1 $cm^2$ is $10^{-4} m^2$ .

$1170839.28 \frac{dyn}{cm^2} * \frac{10^{-8}kN}{1 dyn}*\frac{cm^2}{10^{-4}m^2}=117.083928kN/m^2$

Now passing kN/ $m^2$ to psia. We need to consider that 1 psia is 6.89476.

$117.083928kN/m^2*\frac{1psia}{6.89476kN/m^2}=16.9816 psia$

8 0

3 years ago

You are president of a large corporation. You have a team of experienced VPs. At a typical monthly meeting each of your vice pre

Delicious77 [7]

Answer:

Situational Leadership Model (SLM), which leadership style should you exhibit at the next meeting?

Style 4. Delegating

Explanation:

Situational Leadership is based on the relationship between leaders and followers and serves as a framework to analyze each situation.

Situational Leadership: Delegating

Delegating: When you create a follower who feels fully empowered and competent enough to take the ball and run with it, with minimal supervision. The follower is highly competent, highly committed, motivated, and empowered.

4 0

3 years ago

Your neighbors have offered to pay you to look after their dog while they are on vacation. It will take you one hour per day to

love history [14]

Answer:

C the value you place on one hour of leisure

Explanation:

Here are the options to this question:

OA $15, because overtime wages are generally 1.5 times your regular wage when you work more than eight hours a day OB. $10, because that is your opportunity cost of one hour of work OC the value you place on one hour of leisure OD. zero, because your regular job is not available for more than eight hours per day

Caring for the dog won't interfere with my job as I can care for the dog either before or after work.

What I would be sacrificing to care for the dog would be the time I would have spent resting or doing leisure activities. So the least amount I should charge is the value i place on one hour of leisure.

I hope my answer helps you

8 0

3 years ago